Diketahui segitiga ABC, P membagi AB dengan AP : PB = 2 : 1 dan Q titik tengah AC. Jika C A → = u → \overrightarrow{CA}=\overrightarrow{u} C A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> dan C B → = v → \overrightarrow{CB}=\overrightarrow{v} C B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> , maka P Q → \overrightarrow{PQ} P Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ....

1 6 u → − 2 3 v → \frac{1}{6}\overrightarrow{u}-\frac{2}{3}\overrightarrow{v} 6 1 u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 3 2 v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

1 3 v → − u → \frac{1}{3}\overrightarrow{v}-\overrightarrow{u} 3 1 v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

v → − 1 3 u → \overrightarrow{v}-\frac{1}{3}\overrightarrow{u} v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 3 1 u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

1 3 v → − 1 6 u → \frac{1}{3}\overrightarrow{v}-\frac{1}{6}\overrightarrow{u} 3 1 v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 6 1 u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

1 6 u → + 1 3 v → \frac{1}{6}\overrightarrow{u}+\frac{1}{3}\overrightarrow{v} 6 1 u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 3 1 v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Vector Quiz 1 Kuis

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

ABCD adalah suatu jajar genjang. E merupakan titik di garis BD dengan BE = 1/4 BD. Jika vektor $\overrightarrow{AB}$ = 4a dan $\overrightarrow{AD}$ = 4b. Nyatakan $\overrightarrow{BE}$ dalam a dan b!

a + b

a - b

b - a

-b - a

-b + a

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If w = (2, -5) and y = (2, 0), find 2w + y

(-10, 2)

(4, -5)

(-6, 10)

(6, -10)

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$Nilai\ dari\ \ \ \overrightarrow{p}\ \ +\overrightarrow{\ q}\ +\ \overrightarrow{\ \ r}\ \ \ adalah...$

( 2, 1, 1 )

( -1, 2 , -1 )

( -1, 2, 1 )

( -2, 0, -1 )

( -3, -2, -1 )

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Manakah\ yang\ merupakan\ vektor\ \overrightarrow{\ \ a}\ \ \ +\ \ \overrightarrow{b\ \ }\ \ ?$

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given two vectors :

Manakah hasil dari $\overrightarrow{a\ }\ +\overrightarrow{b\ }$ dengan metode segitiga?

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika koordinat titik E(5, 7) dan F (–2, 3) maka komponen vektor yang diwakili oleh FE adalah…

(3, 4)

(3, -4)

(7, -4)

(7, 4)

(4, 7)

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor $\overrightarrow{KL}$ adalah .....

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika koordinat titik A(-5, 4, 1) dan Vektor $\overrightarrow{AB}$ = (4, -2, 5), Kordinat titik B adalah .... .

(9, -6, 4)

(9, 2, 6)

(-9, 6, -4)

(1, -2, -6)

(-1, 2, 6)

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Vector Quiz 1

ABCD adalah suatu jajar genjang. E merupakan titik di garis BD dengan BE = 1/4 BD. Jika vektor $\overrightarrow{AB}$ = 4a dan $\overrightarrow{AD}$ = 4b. Nyatakan $\overrightarrow{BE}$ dalam a dan b!

If w = (2, -5) and y = (2, 0), find 2w + y

$Nilai\ dari\ \ \ \overrightarrow{p}\ \ +\overrightarrow{\ q}\ +\ \overrightarrow{\ \ r}\ \ \ adalah...$

$Manakah\ yang\ merupakan\ vektor\ \overrightarrow{\ \ a}\ \ \ +\ \ \overrightarrow{b\ \ }\ \ ?$

Given two vectors :

Manakah hasil dari $\overrightarrow{a\ }\ +\overrightarrow{b\ }$ dengan metode segitiga?

Jika koordinat titik E(5, 7) dan F (–2, 3) maka komponen vektor yang diwakili oleh FE adalah…

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor $\overrightarrow{KL}$ adalah .....

Jika koordinat titik A(-5, 4, 1) dan Vektor $\overrightarrow{AB}$ = (4, -2, 5), Kordinat titik B adalah .... .

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

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Popular Resources on Wayground

Discover more resources for Mathematics

Vector Quiz 1

ABCD adalah suatu jajar genjang. E merupakan titik di garis BD dengan BE = 1/4 BD. Jika vektor AB→\overrightarrow{AB}AB = 4a dan AD→\overrightarrow{AD}AD = 4b. Nyatakan BE→\overrightarrow{BE}BE dalam a dan b!

If w = (2, -5) and y = (2, 0), find 2w + y

Nilai dari p→ + q→ + r→ adalah...Nilai\ dari\ \ \ \overrightarrow{p}\ \ +\overrightarrow{\ q}\ +\ \overrightarrow{\ \ r}\ \ \ adalah...Nilai dari p​ + q​ + r adalah...

Manakah yang merupakan vektor a→ + b → ?Manakah\ yang\ merupakan\ vektor\ \overrightarrow{\ \ a}\ \ \ +\ \ \overrightarrow{b\ \ }\ \ ?Manakah yang merupakan vektor a + b ?

Given two vectors :Manakah hasil dari a → +b →\overrightarrow{a\ }\ +\overrightarrow{b\ }a +b dengan metode segitiga?

Jika koordinat titik E(5, 7) dan F (–2, 3) maka komponen vektor yang diwakili oleh FE adalah…

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL→\overrightarrow{KL}KL adalah .....

Jika koordinat titik A(-5, 4, 1) dan Vektor AB→\overrightarrow{AB}AB = (4, -2, 5), Kordinat titik B adalah .... .

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

A = 5i + 7j , B = -6i + 2j makaB - A = ...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

ABCD adalah suatu jajar genjang. E merupakan titik di garis BD dengan BE = 1/4 BD. Jika vektor $\overrightarrow{AB}$ = 4a dan $\overrightarrow{AD}$ = 4b. Nyatakan $\overrightarrow{BE}$ dalam a dan b!

$Nilai\ dari\ \ \ \overrightarrow{p}\ \ +\overrightarrow{\ q}\ +\ \overrightarrow{\ \ r}\ \ \ adalah...$

$Manakah\ yang\ merupakan\ vektor\ \overrightarrow{\ \ a}\ \ \ +\ \ \overrightarrow{b\ \ }\ \ ?$

Given two vectors :

Manakah hasil dari $\overrightarrow{a\ }\ +\overrightarrow{b\ }$ dengan metode segitiga?

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor $\overrightarrow{KL}$ adalah .....

Jika koordinat titik A(-5, 4, 1) dan Vektor $\overrightarrow{AB}$ = (4, -2, 5), Kordinat titik B adalah .... .

A = 5i + 7j , B = -6i + 2j maka
B - A = ...