Wykres funkcji f(x) = (x - 2) 2 + 1 otrzymamy, przesuwając parabolę y = x 2 o:

2 jednostki w prawo i 1 jednostkę w górę

2 jednostki w prawo i 1 jednostkę w dół

2 jednostki w lewo i 1 jednostkę w dół

2 jednostki w lewo i 1 jednostkę w górę

13 4 + 3 = \frac{13}{4+\sqrt{3}}= 4 + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 3 =

4 − 3 4-\sqrt{3} 4 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

13 + 4 3 13+4\sqrt{3} 1 3 + 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

13 ( 4 − 3 ) 13\left(4-\sqrt{3}\right) 1 3 ( 4 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

4 + 3 4+\sqrt{3} 4 + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Kąt α \alpha α jest ostry i t g α = 2 3 tg\alpha=\frac{2}{3} t g α = 3 2 . Wówczas sin ⁡ α = \sin\alpha= sin α =

2 13 13 \frac{2\sqrt{13}}{13} 1 3 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 13 26 \frac{3\sqrt{13}}{26} 2 6 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

13 13 \frac{\sqrt{13}}{13} 1 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 13 13 \frac{3\sqrt{13}}{13} 1 3 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Punkty B(-1;4), i C(5;2) są sąsiednimi wierzchołkami kwadratu ABCD. Pole kwadratu jest równe:

40 \sqrt{40} 4 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

L i c z b a 4 − 1 ⋅ 2 1 4 ⋅ 1 6 1 3 Liczba\ \sqrt{4^{-1}}\cdot2^{\frac{1}{4}}\cdot16^{\frac{1}{3}} L i c z b a 4 − 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ⋅ 2 4 1 ⋅ 1 6 3 1 jest równa

2 7 12 2^{\frac{7}{12}} 2 1 2 7

2 25 12 2^{\frac{25}{12}} 2 1 2 2 5

2 − 1 9 2^{\frac{-1}{9}} 2 9 − 1

Zadania maturalne

Quiz

•

Mathematics

•

1st - 5th Grade

•

Practice Problem

•

Hard

Karolina Faszczewska

Used 83+ times

FREE Resource

25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Ciąg (1,x,16) jest ciągiem geometrycznym dla:

x=4

x=8

x=4 lub x=8

x=4 lub x=-4

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Ile jest liczb dwucyfrowych niepodzielnych przez 5?

90

72

82

76

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1

-1

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

2³⁰

2⁵⁷

2⁶³

2¹¹²

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Wyznacz wzór funkcji liniowej przechodzącej przez punkt A=(0;6), której wykres jest równoległy do wykresu funkcji y=3x+2

y=3x+6

y=-3x+6

y=2

y=6x-2

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Współrzędne punktu przecięcia wykresu funkcji y=-x+6 z osią OY wynoszą:

(0,-6)

(6,0)

(-6,0)

(0,6)

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Wierzchołkiem funkcji kwadratowej y=2(x-3)²-5 jest punkt:

(3;-5)

(3;5)

(-3;-5)

(-3;5)

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

20 questions

GRADOS DE UNA EXPRESIÓN ALGEBRAICA - 3ER GRADO

Quiz

•

3rd Grade

20 questions

FRACCIONES Y DECIMALES

Quiz

•

4th Grade

20 questions

Radicación y propiedades

Quiz

•

3rd Grade

20 questions

Logika Matematika 1B

Quiz

•

1st Grade

20 questions

Class 5 math quiz

Quiz

•

5th - 6th Grade

20 questions

Tables 1

Quiz

•

5th Grade

20 questions

Year 9 - Measurement Revision Quiz 1 TAWA COLLEGE

Quiz

•

3rd - 7th Grade

20 questions

Mate meet Kelas V

Quiz

•

1st - 5th Grade

Popular Resources on Wayground

5 questions

This is not a...winter edition (Drawing game)

Quiz

•

1st - 5th Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

10 questions

Identify Iconic Christmas Movie Scenes

Interactive video

•

6th - 10th Grade

20 questions

Christmas Trivia

Quiz

•

6th - 8th Grade

18 questions

Kids Christmas Trivia

Quiz

•

KG - 5th Grade

11 questions

How well do you know your Christmas Characters?

Lesson

•

3rd Grade

14 questions

Christmas Trivia

Quiz

•

5th Grade

20 questions

How the Grinch Stole Christmas

Quiz

•

5th Grade

Discover more resources for Mathematics

25 questions

Multiplication Facts

Quiz

•

5th Grade

10 questions

Area

Quiz

•

3rd Grade

12 questions

Adding and Subtracting Fractions with Like Denominators

Quiz

•

4th Grade

20 questions

Division Facts

Quiz

•

3rd Grade

25 questions

Division Facts

Quiz

•

3rd Grade

11 questions

Single Digit Divisor Long Division

Quiz

•

5th Grade

22 questions

Christmas Math Fun--5th grade

Quiz

•

4th - 6th Grade

12 questions

Grinch Math

Quiz

•

3rd Grade

Zadania maturalne

25 questions

Ciąg (1,x,16) jest ciągiem geometrycznym dla:

Ile jest liczb dwucyfrowych niepodzielnych przez 5?

Wyznacz wzór funkcji liniowej przechodzącej przez punkt A=(0;6), której wykres jest równoległy do wykresu funkcji y=3x+2

Współrzędne punktu przecięcia wykresu funkcji y=-x+6 z osią OY wynoszą:

Wierzchołkiem funkcji kwadratowej y=2(x-3)²-5 jest punkt:

Wykres funkcji f(x) = (x - 2)² + 1 otrzymamy, przesuwając parabolę y = x² o:

Które z poniższych zdań jest prawdziwe?

Suma pierwiastków równania
(2x-5)(4x+6)(x+1)(1-x³)=0
jest równa:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Zadania maturalne

25 questions

Ciąg (1,x,16) jest ciągiem geometrycznym dla:

Ile jest liczb dwucyfrowych niepodzielnych przez 5?

Wyznacz wzór funkcji liniowej przechodzącej przez punkt A=(0;6), której wykres jest równoległy do wykresu funkcji y=3x+2

Współrzędne punktu przecięcia wykresu funkcji y=-x+6 z osią OY wynoszą:

Wierzchołkiem funkcji kwadratowej y=2(x-3)²-5 jest punkt:

Wykres funkcji f(x) = (x - 2)2 + 1 otrzymamy, przesuwając parabolę y = x2 o:

Które z poniższych zdań jest prawdziwe?

Suma pierwiastków równania(2x-5)(4x+6)(x+1)(1-x3)=0 jest równa:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Wykres funkcji f(x) = (x - 2)² + 1 otrzymamy, przesuwając parabolę y = x² o:

Suma pierwiastków równania
(2x-5)(4x+6)(x+1)(1-x³)=0
jest równa: