Unit 18 - Vectors and Geometric Proof

$\left(3\ 4\right)\ and\ \left(-5\ 8\right)$

$\left(3\ 4\right)\ and\ \left(5\ -8\right)$

$\left(3\ 4\right)\ and\ \left(-6\ 8\right)$

$\left(5\ 4\right)\ and\ \left(6\ 8\right)$

$\left(4\ \ 2\right)$

$\left(4\ -2\right)$

$\left(2\ -1\right)$

$\left(-2\ 1\right)$

$\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a+\frac{1}{2}c$

$\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=-\frac{1}{2}a-\frac{1}{2}c$

$\overrightarrow{MB}=-\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a-\frac{1}{2}c$

$\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a-\frac{1}{2}c$

$\sqrt{29}$

$\sqrt{21}$

$\sqrt{-29}$

$5.4$

$a+b,\ 2\left(a+b\right),3a+3b$

$a+b,\ 2\left(a+b\right),3a+3b,\ 2a+2b$

$a+b,3a+3b,\ 2a+2b$

$2\left(a+b\right),3a+3b,\ 2a+2b$

b-a

-b + a

a + b

-a + b

 $\frac{1}{3}\left(-b+a\right)$  

 $\frac{1}{3}\left(a-b\right)$  

 $\frac{2}{3}\left(-b+a\right)$  

 $\frac{2}{3}\left(-a+b\right)$  

2p - 3q

2p + 3q

-2p + 3q

3q - 2p

 $\frac{6}{5}p\ +\frac{6}{5}q$  

 $\frac{6}{5}p\ -\frac{6}{5}q$  

 $\frac{14}{5}p\ +\frac{6}{5}q$  

 $2p-\frac{4}{5}p+\frac{6}{5}q$  

$\overrightarrow{AE}=4q\ and\ \overrightarrow{AC}=-q+p$

$\overrightarrow{AE}=2q\ and\ \overrightarrow{AC}=q-p$

$\overrightarrow{AE}=2q\ and\ \overrightarrow{AC}=-q+p$

$\overrightarrow{AE}=2q\ and\ \overrightarrow{AC}=q+p$