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Trigonometriskie vienādojumi un nevienādības.

Authored by Inese Jakubova

Mathematics

11th Grade

Used 4+ times

Trigonometriskie vienādojumi un nevienādības.
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15 questions

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1.

MULTIPLE SELECT QUESTION

1 min • 1 pt

 π3+π2=\frac{\pi}{3}+\frac{\pi}{2}=  vairākas atbildes

 5π6\frac{5\pi}{6}  

 150°150\degree  

 2π5\frac{2\pi}{5}  

 120°120\degree  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 sinx=1\sin x=1  

 x= π2+2πnx=\ \frac{\pi}{2}+2\pi n  

 x=π2+2πnx=-\frac{\pi}{2}+2\pi n  

 x=π+2πnx=\pi+2\pi n  

 x=2πnx=2\pi n  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 cosx=1\cos x=1  

 x= π2+2πnx=\ \frac{\pi}{2}+2\pi n  

 x=π2+2πnx=-\frac{\pi}{2}+2\pi n  

 x=π+2πnx=\pi+2\pi n  

 x=2πnx=2\pi n  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 cosx=1\cos x=-1  

 x= π2+2πnx=\ \frac{\pi}{2}+2\pi n  

 x=π2+2πnx=-\frac{\pi}{2}+2\pi n  

 x=π+2πnx=\pi+2\pi n  

 x=2πnx=2\pi n  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 sinx=1\sin x=-1  

 x= π2+2πnx=\ \frac{\pi}{2}+2\pi n  

 x=π2+2πnx=-\frac{\pi}{2}+2\pi n  

 x=π+2πnx=\pi+2\pi n  

 x=2πnx=2\pi n  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 tgx=3tgx=\sqrt{3}  

 x=π3+πnx=\frac{\pi}{3}+\pi n  

 x=π6+πnx=\frac{\pi}{6}+\pi n  

 x=π3+πnx=-\frac{\pi}{3}+\pi n  

 x=π6+πnx=-\frac{\pi}{6}+\pi n  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 ctgx=3\operatorname{ctg}x=\sqrt{3}  

 x=π3+πnx=\frac{\pi}{3}+\pi n  

 x=π6+πnx=\frac{\pi}{6}+\pi n  

 x=π3+πnx=-\frac{\pi}{3}+\pi n  

 x=π6+πnx=-\frac{\pi}{6}+\pi n  

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