U7 L17-19

Write the equation of a circle with center (7, 0) with radius 3.

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

Tags

CCSS.HSG.GPE.A.1

What are the coordinates of the center and the radius of the circle with equation (x - 4)² + (y - 3)² = 25 ?

• Center (4, 3)

  Radius = 5 units

• Center (4, 3)

  Radius = 25 units

• Center (-4, -3)

  Radius = 25 units

• Center (-4, -3)

  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0, 0) and radius of 3.

• x² + y² = 4

• x² + y² = 81

• x² + y² = 9

• x² + y² = 3

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

Tags

CCSS.HSG.GPE.A.1

What is the radius of the circle with this equation of (x - 5)² + (y + 7)² = 8?

• 4

• 8

• 4√2

• 2√2

Tags

CCSS.HSG.GPE.A.1

What is the radius of the circle given by the equation (x - 7)² + (y + 3)² = 25?

• 3

• 5

• 10

• 25

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

A circle has the equation x² + y² - 12x + 8y + 3 = 0. Write the equation in standard form.

• (x - 6)² + (y + 4)² = 49

• (x + 4)² + (y - 6)² = 49

• (x - 6)² + (y + 4)² = 55

• x² + y² = 55

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form

x² + y² - 4x + 12y - 8 = 0

• (x + 2)² + (y - 6)² = 48

• (x - 2)² + (y + 6)² = 48

• (x - 6)² + (y - 2)² = 48

• (x + 2)² + (y - 6)² = 48

Tags

CCSS.HSG.GPE.A.1

Write the equation of the circle with center C( -5 , 8 ) and radius = 7

• ( x - 5 )² + ( y + 8 )² = 14

• ( x - 5 )² + ( y - 8 )² = 49

• ( x - 5 )² + ( y + 8 )² = 49

• ( x + 5 )² + ( y - 8 )² = 49

Tags

CCSS.HSG.GPE.A.1