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Invers Logaritma Natural

Authored by Yessi Affri

Mathematics

University

Used 20+ times

Invers Logaritma Natural
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi f merupakan fungsi injektif jika  x1≠x2x_1\ne x_2  sedemikian hingga...

 f(x1)≠f(x2)f\left(x_1\right)\ne f\left(x_2\right)  

 f(x1)=f(x2)f\left(x_1\right)=f\left(x_2\right)  

 f(x1)≥f(x2)f\left(x_1\right)\ge f\left(x_2\right)  

 f(x1)≤f(x2)f\left(x_1\right)\le f\left(x_2\right)  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi injeksi f memiliki invers  f−1f^{-1}   yang memenuhi  f−1(f(x))=f^{-1}\left(f\left(x\right)\right)=  _____

 f(x)f\left(x\right)  

y

x

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi injeksi f memiliki invers  f−1f^{-1}  yang memenuhi  f(......)f\left(......\right) = y

 f−1(y)f^{-1}\left(y\right)  

y

x

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Kriteria berguna untuk f yang injektif (dengan demikian juga memiliki invers) pada suatu domain adalah f harus _____ yang bermakna bahwa f _____ atau _____.

Beragam; Naik; Turun

Beragam; Terbuka; Tertutup

Monoton; Naik; Turun

Monoton; Terbuka; Tertutup

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Jika  y=f(x)y=f\left(x\right)  , dimana f memiliki invers  f−1f^{-1}  . Persamaan yang menghubungkan f dan  f−1f^{-1}   adalah...

 (f−1)′(y)=f′(x)\left(f^{-1}\right)'\left(y\right)=f'\left(x\right)  

 (f−1)′(y)=1f′(x)\left(f^{-1}\right)'\left(y\right)=\frac{1}{f'\left(x\right)}  

 (f−1)′(y)=f−1(x)\left(f^{-1}\right)'\left(y\right)=f^{-1}\left(x\right)  

 (f−1)′(y)=1f−1(x)\left(f^{-1}\right)'\left(y\right)=\frac{1}{f^{-1}\left(x\right)}  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi ln _____ pada  \left(0,\infty\right) sehingga memiliki invers yang dapat dituliskan sebagai  ln⁡−1\ln^{-1}  atau _____

Naik;  1ln⁡\frac{1}{\ln}  

Naik; exp

Turun;  1ln⁡\frac{1}{\ln}  

Turun; exp

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Bilangan e terdefinisi dalam ln sebagai _____

ln⁡e=e\ln e=e

ln⁡e=2,72\ln e=2,72

ln⁡e=1\ln e=1

ln⁡e=1e\ln e=\frac{1}{e}

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