Trig Review 3 M

In triangle ABC, A is a right angle, B is 60^o, what is sinC? B+C=90, so C=90-B.

PQ = 3 and QR = 4, what is the measure of angle P? Use tangent to solve the problem.  $\tan P=\frac{QR}{PQ},\ so\ P=\tan^{-1}\left(\frac{QR}{PQ}\right)$  

Find cosA. $\cos A=\frac{adjacent}{hypotenuse}$  

Find sinQ. $\sin Q=\frac{opposite}{hypotenuse}$  

Find cos(30).

Find tan(13)

If  $\theta=18$ , find cos( $90-\theta$ ).

Find the area of the triangle. $A=\frac{1}{2}ab\sin\left(63\right),\ a=7.9,\ b=6.2$