Algebra 1 9.1.3 to 9.1.4 Quiz

What should you do first in solving this equation?
 $x^2+6x-13=3$  

• Factor

• Write down: a = 1, b = 6, c = -13

• Subtract 3 from both sides.

• Add 3 to both sides.

What is a, b and c for the following equation?
 $x^2+6x-16=0$  

•  $a=1,\ b=6,\ c=-16$ 

•  $a=x^2,\ b=6,\ c=-16$  

•  $a=1,\ b\ =\ 6,\ c\ =16$  

•  $a=x^2,\ b=6x,\ c=-16$  

Which is the correct use of the quadratic formula for the following equation? 
 $x^2+6x-16=0$  

•  $x=\frac{6\pm\sqrt{\left(6\right)^2-4\left(1\right)\left(16\right)}}{2\left(1\right)}$  

•  $x=\frac{-6\pm\sqrt{\left(6\right)^2-4\left(1\right)\left(-16\right)}}{2\left(1\right)}$  

•  $x=\frac{-6\pm\sqrt{\left(6\right)^2-4\left(x^2\right)\left(-16\right)}}{2\left(x^2\right)}$  

•  $x=\frac{6\pm\sqrt{\left(6\right)^2+4\left(1\right)\left(16\right)}}{2\left(1\right)}$  

What is the correct solution for the following equation?
 $x^2+6x-16=0$  

•  $x=2$  

•  $x=-8$  

•  $x=2,\ x=-8$   

•  $x=8,\ x=-2$  

Use the quadratic formula to find the solutions for

 $0=-x^2-5x+12$  

• No Real Solution

• 
• 
•