Hasil ( 2 , − 1 , 5 ) + 2 ( − 3 , 4 , 1 ) = . . . \left(2,\ -1,\ 5\right)+2\left(-3,\ 4,\ 1\right)=... ( 2 , − 1 , 5 ) + 2 ( − 3 , 4 , 1 ) = . . .

( − 4 , 7 , 7 ) \left(-4,\ 7,\ 7\right) ( − 4 , 7 , 7 )

( − 1 , 3 , 6 ) \left(-1,\ 3,\ 6\right) ( − 1 , 3 , 6 )

( − 4 , 3 , 7 ) \left(-4,\ 3,\ 7\right) ( − 4 , 3 , 7 )

( − 3 , 6 , 6 ) \left(-3,\ 6,\ 6\right) ( − 3 , 6 , 6 )

Jika koordinat titik A ( − 4 , 1 , − 3 ) A\left(-4,\ 1,\ -3\right) A ( − 4 , 1 , − 3 ) dan B ( 2 , 5 , − 4 ) B\left(2,\ 5,\ -4\right) B ( 2 , 5 , − 4 ) vektor A B → = . . . \overrightarrow{AB}=... A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = . . .

( 6 , 4 , − 1 ) \left(6,\ 4,\ -1\right) ( 6 , 4 , − 1 )

( 6 , 4 , 1 ) \left(6,\ 4,\ 1\right) ( 6 , 4 , 1 )

( 6 , − 4 , 1 ) \left(6,\ -4,\ 1\right) ( 6 , − 4 , 1 )

( − 6 , − 4 , 1 ) \left(-6,\ -4,\ 1\right) ( − 6 , − 4 , 1 )

Diketahui vektor a → = ( 3 , 1 , 2 ) , b → = ( − 4 , 3 , 5 ) \overrightarrow{\ a\ }=\left(3,\ 1,\ 2\right),\ \overrightarrow{\ b\ }=\left(-4,\ 3,\ 5\right) a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 1 , 2 ) , b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 4 , 3 , 5 ) dan c → = ( 3 , − 2 , 2 ) \overrightarrow{\ c\ }=\left(3,\ -2,\ 2\right) c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , − 2 , 2 ) . Vektor a → − 2 b → + 3 c → \overrightarrow{\ a}-2\overrightarrow{b\ }+3\overrightarrow{\ c\ } a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 2 b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 3 c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah

( 20 , − 11 , − 2 ) \left(20,\ -11,\ -2\right) ( 2 0 , − 1 1 , − 2 )

( 18 , − 11 , 1 ) \left(18,\ -11,\ 1\right) ( 1 8 , − 1 1 , 1 )

( 20 , − 11 , − 4 ) \left(20,\ -11,\ -4\right) ( 2 0 , − 1 1 , − 4 )

( 20 , − 11 , 5 ) \left(20,\ -11,\ 5\right) ( 2 0 , − 1 1 , 5 )

Diketahui koordinat titik P ( 0 , 3 , 2 ) P\left(0,\ 3,\ 2\right) P ( 0 , 3 , 2 ) dan Q ( 3 , 6 , − 1 ) Q\left(3,\ 6,\ -1\right) Q ( 3 , 6 , − 1 ) . Vektor satuan dari P Q → \overrightarrow{\ PQ\ } P Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah

1 3 ( i + j − k ) \frac{1}{\sqrt{3}}\left(i+j-k\right) 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ( i + j − k )

1 3 ( − i − j − k ) \frac{1}{\sqrt{3}}\left(-i-j-k\right) 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ( − i − j − k )

1 3 ( − i + j + k ) \frac{1}{\sqrt{3}}\left(-i+j+k\right) 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ( − i + j + k )

1 3 ( i − j − k ) \frac{1}{\sqrt{3}}\left(i-j-k\right) 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ( i − j − k )

Operasi Vektor di R3

Authored by Askia Nurzakia

Mathematics

10th Grade

CCSS covered

Used 26+ times

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10 questions

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MULTIPLE SELECT QUESTION

2 mins • 1 pt

Hasil $\left(2,\ -1,\ 5\right)+2\left(-3,\ 4,\ 1\right)=...$

$\left(-1,\ 3,\ 6\right)$

$\left(-4,\ 3,\ 7\right)$

$\left(-4,\ 7,\ 7\right)$

$\left(-3,\ 6,\ 6\right)$

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Jika koordinat titik $A\left(-4,\ 1,\ -3\right)$ dan $B\left(2,\ 5,\ -4\right)$ vektor $\overrightarrow{AB}=...$

$\left(6,\ 4,\ 1\right)$

$\left(6,\ -4,\ 1\right)$

$\left(-6,\ -4,\ 1\right)$

$\left(6,\ 4,\ -1\right)$

MULTIPLE SELECT QUESTION

3 mins • 1 pt

Diketahui vektor $\overrightarrow{\ a\ }=\left(3,\ 1,\ 2\right),\ \overrightarrow{\ b\ }=\left(-4,\ 3,\ 5\right)$ dan $\overrightarrow{\ c\ }=\left(3,\ -2,\ 2\right)$ . Vektor $\overrightarrow{\ a}-2\overrightarrow{b\ }+3\overrightarrow{\ c\ }$ adalah

$\left(18,\ -11,\ 1\right)$

$\left(20,\ -11,\ -4\right)$

$\left(20,\ -11,\ 5\right)$

$\left(20,\ -11,\ -2\right)$

MULTIPLE SELECT QUESTION

3 mins • 1 pt

Diketahui koordinat titik $P\left(0,\ 3,\ 2\right)$ dan $Q\left(3,\ 6,\ -1\right)$ . Vektor satuan dari $\overrightarrow{\ PQ\ }$ adalah

$\frac{1}{\sqrt{3}}\left(-i-j-k\right)$

$\frac{1}{\sqrt{3}}\left(i+j-k\right)$

$\frac{1}{\sqrt{3}}\left(-i+j+k\right)$

$\frac{1}{\sqrt{3}}\left(i-j-k\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Tentukan\ vektor\ posisi\ \overrightarrow{OA}!$

$(2,5,3)$

$(2,-5,3)$

$(2,-5,-3)$

$(-2,-5,3)$

$(-2,-5,-3)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Panjang vektor $\overrightarrow{r}=14i+2j-5k$ adalah....

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Diketahui vektor-vektor berikut: $\overrightarrow{b}=5\overline{i}+4\overline{j}-\overline{k}$ dan $\overrightarrow{c}=4\overline{i}-\overline{j}+\overline{k}$ . panjang dari vektor $\overrightarrow{b}-\overrightarrow{c}$ adalah...

$5\sqrt{3}$

$5\sqrt{6}$

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Operasi Vektor di R3

Hasil $\left(2,\ -1,\ 5\right)+2\left(-3,\ 4,\ 1\right)=...$

Jika koordinat titik $A\left(-4,\ 1,\ -3\right)$ dan $B\left(2,\ 5,\ -4\right)$ vektor $\overrightarrow{AB}=...$

Diketahui vektor $\overrightarrow{\ a\ }=\left(3,\ 1,\ 2\right),\ \overrightarrow{\ b\ }=\left(-4,\ 3,\ 5\right)$ dan $\overrightarrow{\ c\ }=\left(3,\ -2,\ 2\right)$ . Vektor $\overrightarrow{\ a}-2\overrightarrow{b\ }+3\overrightarrow{\ c\ }$ adalah

Diketahui koordinat titik $P\left(0,\ 3,\ 2\right)$ dan $Q\left(3,\ 6,\ -1\right)$ . Vektor satuan dari $\overrightarrow{\ PQ\ }$ adalah

$Tentukan\ vektor\ posisi\ \overrightarrow{OA}!$

Panjang vektor $\overrightarrow{r}=14i+2j-5k$ adalah....

Diketahui vektor-vektor berikut: $\overrightarrow{b}=5\overline{i}+4\overline{j}-\overline{k}$ dan $\overrightarrow{c}=4\overline{i}-\overline{j}+\overline{k}$ . panjang dari vektor $\overrightarrow{b}-\overrightarrow{c}$ adalah...

berikut yang termasuk kelompok besaran vektor adalah

diketahui titik A (3, 1, -4), B(3, -4, 6) dan C (-1, 5, 4). titik P membagi AB sehingga AP : PB = 3 : 2, maka vektor yang diwakili oleh PC adalah ......

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Operasi Vektor di R3

Hasil (2, −1, 5)+2(−3, 4, 1)=...\left(2,\ -1,\ 5\right)+2\left(-3,\ 4,\ 1\right)=...(2, −1, 5)+2(−3, 4, 1)=...

Jika koordinat titik A(−4, 1, −3)A\left(-4,\ 1,\ -3\right)A(−4, 1, −3) dan B(2, 5, −4)B\left(2,\ 5,\ -4\right)B(2, 5, −4) vektor AB→=...\overrightarrow{AB}=...AB=...

Diketahui koordinat titik P(0, 3, 2)P\left(0,\ 3,\ 2\right)P(0, 3, 2) dan Q(3, 6, −1)Q\left(3,\ 6,\ -1\right)Q(3, 6, −1) . Vektor satuan dari PQ →\overrightarrow{\ PQ\ } PQ ​ adalah

Tentukan vektor posisi OA→!Tentukan\ vektor\ posisi\ \overrightarrow{OA}!Tentukan vektor posisi OA!

Panjang vektor \overrightarrow{r}=14i+2j-5kr=14i+2j−5k adalah....

berikut yang termasuk kelompok besaran vektor adalah

diketahui titik A (3, 1, -4), B(3, -4, 6) dan C (-1, 5, 4). titik P membagi AB sehingga AP : PB = 3 : 2, maka vektor yang diwakili oleh PC adalah ......

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Popular Resources on Wayground

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Hasil $\left(2,\ -1,\ 5\right)+2\left(-3,\ 4,\ 1\right)=...$

Jika koordinat titik $A\left(-4,\ 1,\ -3\right)$ dan $B\left(2,\ 5,\ -4\right)$ vektor $\overrightarrow{AB}=...$

Diketahui koordinat titik $P\left(0,\ 3,\ 2\right)$ dan $Q\left(3,\ 6,\ -1\right)$ . Vektor satuan dari $\overrightarrow{\ PQ\ }$ adalah

$Tentukan\ vektor\ posisi\ \overrightarrow{OA}!$

Panjang vektor $\overrightarrow{r}=14i+2j-5k$ adalah....