N i l a i tan ⁡ 165 ° = . . . . Nilai\ \tan165\degree=.... N i l a i tan 1 6 5 ° = . . . .

− 2 − 3 -2-\sqrt{3} − 2 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 + 3 -2+\sqrt{3} − 2 + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 − 2 \sqrt{3}-2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2

− 1 − 3 -1-\sqrt{3} − 1 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 − 3 1-\sqrt{3} 1 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

J i k a A + B = 45 ° \ Jika\ A+B=45\degree J i k a A + B = 4 5 ° maka tan B = ....

1 − tan ⁡ A 1 + tan ⁡ A \frac{1-\tan\ A}{1+\tan\ A} 1 + tan A 1 − tan A

2 tan ⁡ A 1 − tan ⁡ B \frac{2\tan\ A\ }{1-\tan\ B} 1 − tan B 2 tan A

1 + tan ⁡ A 1 − tan ⁡ A \frac{1+\tan\ A\ }{1-\tan\ A} 1 − tan A 1 + tan A

J i k a sin ⁡ ( x + 30 ° ) = sin ⁡ x , m a k a tan ⁡ x = . . . . Jika\ \sin\left(x+30\degree\right)=\sin\ x,\ maka\ \tan\ x=.... J i k a sin ( x + 3 0 ° ) = sin x , m a k a tan x = . . . .

2 + 3 2+\sqrt{3} 2 + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 − 3 2-\sqrt{3} 2 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 − 1 2 3 1-\frac{1}{2}\sqrt{3} 1 − 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 + 1 2 3 1+\frac{1}{2}\sqrt{3} 1 + 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 − 2 \sqrt{3}-2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2

RUMUS JUMLAH DAN SELISIH DUA SUDUT

Authored by Diah Ayuningtias

Mathematics

11th Grade

Used 75+ times

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10 questions

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

sin 50^o cos 10^o + cos 50^osin 10^o=

sin 40^o

sin 50^o

sin 60^o

cos 40^o

cos 60^o

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Misal sin $40\degree$ = A, maka sin $130\degree$ =....

$\sqrt{1+a^2}$

$\frac{1}{\sqrt{1+a^{2\ }}}$

$1-\sqrt{1+a^2}$

$\sqrt{1-a^2}$

$\frac{1}{\sqrt{1-a^2}}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$Nilai\ \tan165\degree=....$

$-2-\sqrt{3}$

$-2+\sqrt{3}$

$\sqrt{3}-2$

$-1-\sqrt{3}$

$1-\sqrt{3}$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\ Jika\ A+B=45\degree$ maka tan B = ....

$\frac{2\tan\ A\ }{1-\tan\ B}$

$\frac{1+\tan\ A\ }{1-\tan\ A}$

$\frac{1-\tan\ A}{1+\tan\ A}$

2 tan A

tan A

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$Bentuk\ sederhana\ dari\ \cos\ 78\degree-\sin\ 78\degree.\cot\ 39\degree\ adalah.....$

$\tan\ 39\degree$

$\cot\ 39\degree$

$-1$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$Jika\ \sin\left(x+30\degree\right)=\sin\ x,\ maka\ \tan\ x=....$

$2+\sqrt{3}$

$2-\sqrt{3}$

$1-\frac{1}{2}\sqrt{3}$

$1+\frac{1}{2}\sqrt{3}$

$\sqrt{3}-2$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$Jika\ \tan\ A=\frac{3}{4\ }\ dan\ \tan\ B=\frac{1}{7}\ dengan\ A\ dan\ B\ lancip,\ maka\ \cos\left(A+B\right)=....$

$\sqrt{2}$

$\frac{1}{2}\sqrt{2}$

$\frac{1}{4}\sqrt{2}$

$\frac{1}{10}\sqrt{2}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Perhatikan gambar berikut. Nilai dari sin A = ....

$\frac{15}{34}$

$\frac{19}{34}$

$\frac{30}{34}$

$\frac{15}{16}$

$\frac{16}{17}$

10.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$Jika\ 2\cos\ \left(x+45\degree\right)-\cos\ \left(x-45\degree\right)=0,\ maka\ \cot\ x=....$

1/3

1/2

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RUMUS JUMLAH DAN SELISIH DUA SUDUT

sin 50o cos 10o + cos 50o sin 10o =

Misal sin 40°40\degree40° = A, maka sin 130°130\degree130° =....

Nilai tan⁡165°=....Nilai\ \tan165\degree=....Nilai tan165°=....

Jika A+B=45°\ Jika\ A+B=45\degree Jika A+B=45° maka tan B = ....

Bentuk sederhana dari cos⁡ 78°−sin⁡ 78°.cot⁡ 39° adalah.....Bentuk\ sederhana\ dari\ \cos\ 78\degree-\sin\ 78\degree.\cot\ 39\degree\ adalah.....Bentuk sederhana dari cos 78°−sin 78°.cot 39° adalah.....

Jika sin⁡(x+30°)=sin⁡ x, maka tan⁡ x=....Jika\ \sin\left(x+30\degree\right)=\sin\ x,\ maka\ \tan\ x=....Jika sin(x+30°)=sin x, maka tan x=....

Jika tan⁡ A=34 dan tan⁡ B=17 dengan A dan B lancip, maka cos⁡(A+B)=....Jika\ \tan\ A=\frac{3}{4\ }\ dan\ \tan\ B=\frac{1}{7}\ dengan\ A\ dan\ B\ lancip,\ maka\ \cos\left(A+B\right)=....Jika tan A=4 3​ dan tan B=71​ dengan A dan B lancip, maka cos(A+B)=....

Perhatikan gambar berikut. Nilai dari sin A = ....

Misal cos(A-B)=0,5 dan cos A cos B = 0,1, maka sin A sin B=....

Jika 2cos⁡ (x+45°)−cos⁡ (x−45°)=0, maka cot⁡ x=....Jika\ 2\cos\ \left(x+45\degree\right)-\cos\ \left(x-45\degree\right)=0,\ maka\ \cot\ x=....Jika 2cos (x+45°)−cos (x−45°)=0, maka cot x=....

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sin 50^o cos 10^o + cos 50^osin 10^o=

Misal sin $40\degree$ = A, maka sin $130\degree$ =....

$Nilai\ \tan165\degree=....$

$\ Jika\ A+B=45\degree$ maka tan B = ....

$Bentuk\ sederhana\ dari\ \cos\ 78\degree-\sin\ 78\degree.\cot\ 39\degree\ adalah.....$

$Jika\ \sin\left(x+30\degree\right)=\sin\ x,\ maka\ \tan\ x=....$

$Jika\ \tan\ A=\frac{3}{4\ }\ dan\ \tan\ B=\frac{1}{7}\ dengan\ A\ dan\ B\ lancip,\ maka\ \cos\left(A+B\right)=....$

$Jika\ 2\cos\ \left(x+45\degree\right)-\cos\ \left(x-45\degree\right)=0,\ maka\ \cot\ x=....$