Factoring ax^2+bx+c

 $\left(x+1\right)\left(3x+11\right)$  

 $\left(x+11\right)\left(3x+1\right)$  

 $\left(x+33\right)\left(3x+1\right)$  

 $\left(x+1\right)\left(3x+33\right)$  

 $\left(x-2\right)\left(7x-2\right)$  

 $\left(x+4\right)\left(7x+1\right)$  

 $\left(x+1\right)\left(7x+4\right)$  

 $\left(x+2\right)\left(7x+2\right)$  

 $\left(2x+3\right)\left(3x+3\right)$  

 $\left(x+9\right)\left(3x+1\right)$  

 $\left(2x+1\right)\left(3x+9\right)$  

 $\left(2x+9\right)\left(3x+1\right)$  

 $\left(3x+5\right)^2$  

 $\left(3x+25\right)\left(3x+1\right)$  

 $\left(x+5\right)\left(9x+5\right)$  

 $\left(x+1\right)\left(9x+25\right)$  

 $\left(32x-9\right)\left(2x-1\right)$  

 $\left(8x-3\right)^2$  

 $\left(64x-3\right)\left(x-3\right)$  

 $\left(16x-9\right)\left(4x-1\right)$  

A quadratic can not be factored

A quadratic can not be solved

A quadratic is not in standard form

A quadratic is only divisible by prime numbers

 $\left(5x+7\right)\left(x-1\right)$  

 $\left(5x-7\right)\left(x+1\right)$ 

 $\left(5x+1\right)\left(x-7\right)$  

 $\left(5x-1\right)\left(x+7\right)$  

prime

 $\left(x+4\right)\left(7x+1\right)$  

 $\left(x+1\right)\left(7x+4\right)$  

 $\left(x+2\right)\left(7x+2\right)$  

(5v - 8)(v + 5)

(5v + 5)(v - 8)

5(v - 4)(v - 2)

5(v + 8)(v - 5)

(q + 9)(q + 1)

3(q + 9)(q + 1)

(q + 9)(q + 3)

3(q + 9)(q + 3)