wzory redukcyjne i tożsamości trygonometryczne

wzory redukcyjne i tożsamości trygonometryczne

1st - 6th Grade

20 Qs

quiz-placeholder

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wzory redukcyjne i tożsamości trygonometryczne

wzory redukcyjne i tożsamości trygonometryczne

Assessment

Quiz

Mathematics

1st - 6th Grade

Practice Problem

Medium

Created by

Marta Zalas

Used 90+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

sin(90°+α)=cosα\sin\left(90\degree+\alpha\right)=\cos\alpha

sin(90°+α)=cosα\sin\left(90\degree+\alpha\right)=-\cos\alpha

sin(90°+α)=sinα\sin\left(90\degree+\alpha\right)=\sin\alpha

sin(90°+α)=sinα\sin\left(90\degree+\alpha\right)=-\sin\alpha

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

sin(180°+α)=cosα\sin\left(180\degree+\alpha\right)=\cos\alpha

sin(180°+α)=cosα\sin\left(180\degree+\alpha\right)=-\cos\alpha

sin(180°+α)=sinα\sin\left(180\degree+\alpha\right)=\sin\alpha

sin(180°+α)=sinα\sin\left(180\degree+\alpha\right)=-\sin\alpha

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

sin(180°α)=cosα\sin\left(180\degree-\alpha\right)=\cos\alpha

sin(180°α)=cosα\sin\left(180\degree-\alpha\right)=-\cos\alpha

sin(180°α)=sinα\sin\left(180\degree-\alpha\right)=\sin\alpha

sin(180°α)=sinα\sin\left(180\degree-\alpha\right)=-\sin\alpha

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

cos(180°+α)=cosα\cos\left(180\degree+\alpha\right)=\cos\alpha

cos(180°+α)=cosα\cos\left(180\degree+\alpha\right)=-\cos\alpha

cos(180°+α)=sinα\cos\left(180\degree+\alpha\right)=\sin\alpha

cos(180°+α)=sinα\cos\left(180\degree+\alpha\right)=-\sin\alpha

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

cos(90°+α)=cosα\cos\left(90\degree+\alpha\right)=\cos\alpha

cos(90°+α)=cosα\cos\left(90\degree+\alpha\right)=-\cos\alpha

cos(90°+α)=sinα\cos\left(90\degree+\alpha\right)=\sin\alpha

cos(90°+α)=sinα\cos\left(90\degree+\alpha\right)=-\sin\alpha

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Wskaż równość prawdziwą

tg(180°+α)=tgαtg\left(180\degree+\alpha\right)=tg\alpha

tg(180°+α)=tgαtg\left(180\degree+\alpha\right)=-tg\alpha

tg(180°+α)=ctgαtg\left(180\degree+\alpha\right)=\operatorname{ctg}\alpha

tg(180°+α)=ctgαtg\left(180\degree+\alpha\right)=-\operatorname{ctg}\alpha

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

cos(180o + x) =

cosx

sinx

-cosx

-sinx

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