Order of Operations with Positive and Negative numbers. C2

7th - 9th Grade

•

12 Qs

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Order of Operations with Positive and Negative numbers. C2

Quiz

•

Mathematics

•

7th - 9th Grade

•

Practice Problem

•

Hard

•

CCSS

7.NS.A.3, 7.NS.A.1D, 7.EE.B.3

Standards-aligned

Katie Barlas

Used 54+ times

FREE Resource

12 questions

Show all answers

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$\left(-3\right)+\left(-3\right)\left(-3\right)-\frac{\left(-3\right)}{\left(+3\right)}\ =$

Tags

CCSS.7.NS.A.1D

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$8-2\cdot3-9=$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$8-2\left(3-9\right)=$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$16\cdot\left(-24\right)+50=$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$40-3^2-2^3\ =$

Tags

CCSS.6.EE.A.1

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$4\cdot\left(6+8\right)\div\left(4+3\right)=$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$4\cdot5-2+4=$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$8\left(-7\right)+6\left(-5\right)=$

Tags

CCSS.7.EE.B.3

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$20\div5\left(3\right)+3=$

Tags

CCSS.7.EE.B.3

10.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

$8\div2\cdot0\div6=$

Tags

CCSS.7.NS.A.3

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Order of Operations with Positive and Negative numbers. C2

12 questions

(−3)+(−3)(−3)−(−3)(+3) =\left(-3\right)+\left(-3\right)\left(-3\right)-\frac{\left(-3\right)}{\left(+3\right)}\ =(−3)+(−3)(−3)−(+3)(−3)​ =

8−2⋅3−9=8-2\cdot3-9=8−2⋅3−9=

8−2(3−9)=8-2\left(3-9\right)=8−2(3−9)=

16⋅(−24)+50=16\cdot\left(-24\right)+50=16⋅(−24)+50=

40−32−23 =40-3^2-2^3\ =40−32−23 =

4⋅(6+8)÷(4+3)=4\cdot\left(6+8\right)\div\left(4+3\right)=4⋅(6+8)÷(4+3)=

4⋅5−2+4=4\cdot5-2+4=4⋅5−2+4=

8(−7)+6(−5)=8\left(-7\right)+6\left(-5\right)=8(−7)+6(−5)=

20÷5(3)+3=20\div5\left(3\right)+3=20÷5(3)+3=

8÷2⋅0÷6=8\div2\cdot0\div6=8÷2⋅0÷6=

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$\left(-3\right)+\left(-3\right)\left(-3\right)-\frac{\left(-3\right)}{\left(+3\right)}\ =$

$8-2\cdot3-9=$

$8-2\left(3-9\right)=$

$16\cdot\left(-24\right)+50=$

$40-3^2-2^3\ =$

$4\cdot\left(6+8\right)\div\left(4+3\right)=$

$4\cdot5-2+4=$

$8\left(-7\right)+6\left(-5\right)=$

$20\div5\left(3\right)+3=$

$8\div2\cdot0\div6=$