Fungsi f ditentukan oleh f ( x ) = 2 x + 1 x − 3 , x ≠ 3 f\left(x\right)=\frac{2x+1}{x-3},\ x\ne3 f ( x ) = x − 3 2 x + 1 , x  = 3 jika f − 1 f^{-1} f − 1 invers dari f, maka f − 1 ( x + 1 ) = f^{-1}\left(x+1\right)= f − 1 ( x + 1 ) = ...

3 x + 1 x − 2 , x ≠ 2 \frac{3x+1}{x-2},\ x\ \ne2 x − 2 3 x + 1 , x  = 2

3 x − 1 x − 2 , x ≠ 2 \frac{3x-1}{x-2},\ x\ne2 x − 2 3 x − 1 , x  = 2

3 x + 2 x − 1 , x ≠ 1 \frac{3x+2}{x-1},\ x\ne1 x − 1 3 x + 2 , x  = 1

3 x + 2 x + 1 , x ≠ − 1 \frac{3x+2}{x+1},\ x\ne-1 x + 1 3 x + 2 , x  = − 1

3 x + 4 x − 1 , x ≠ 1 \frac{3x+4}{x-1},\ x\ne1 x − 1 3 x + 4 , x  = 1

Jika f(x) = x – 3 dan g (x) = 3 – 2x, maka ( f ∘ g ) − 1 = \left(f\ \circ\ g\right)^{-1}= ( f ∘ g ) − 1 = adalah

− 1 2 x -\frac{1}{2}x − 2 1 x

3 − 1 2 x 3-\frac{1}{2}x 3 − 2 1 x

1 2 x − 3 \frac{1}{2}x-3 2 1 x − 3

Diketahui f ( x ) = x x − 1 f\left(x\right)=\frac{x}{x-1} f ( x ) = x − 1 x untuk x ≠ 1 x\ne1 x  = 1 . Fungsi invers f ( x ) f\left(x\right) f ( x ) adalah ...

x x − 1 \frac{x}{x-1} x − 1 x

x − 1 x \frac{x-1}{x} x x − 1

1 x − 1 \frac{1}{x-1} x − 1 1

Diketahui f = { ( 1 , 1 ) , ( 2 , 3 ) , ( 3 , 5 ) , ( 5 , 7 ) } f=\left\{\left(1,1\right),\left(2,3\right),\left(3,5\right),\left(5,7\right)\right\} f = { ( 1 , 1 ) , ( 2 , 3 ) , ( 3 , 5 ) , ( 5 , 7 ) } dan g = { ( 1 , 3 ) , ( 3 , 5 ) , ( 5 , 7 ) } g=\left\{\left(1,3\right),\left(3,5\right),\left(5,7\right)\right\} g = { ( 1 , 3 ) , ( 3 , 5 ) , ( 5 , 7 ) } . Komposisi ( f o g ) = . . . . \left(fo\ g\right)=.... ( f o g ) = . . . .

{ ( 1 , 5 ) , ( 3 , 7 ) } \left\{\left(1,5\right),\left(3,7\right)\right\} { ( 1 , 5 ) , ( 3 , 7 ) }

{ ( 1 , 5 ) , ( 3 , 5 ) } \left\{\left(1,5\right),\left(3,5\right)\right\} { ( 1 , 5 ) , ( 3 , 5 ) }

{ ( 1 , 3 ) , ( 3 , 7 ) } \left\{\left(1,3\right),\left(3,7\right)\right\} { ( 1 , 3 ) , ( 3 , 7 ) }

{ ( 1 , 5 ) , ( 3 , 7 ) , ( 7 , 4 ) } \left\{\left(1,5\right),\left(3,7\right),\left(7,4\right)\right\} { ( 1 , 5 ) , ( 3 , 7 ) , ( 7 , 4 ) }

{ ( 1 , 5 ) , ( 3 , 7 ) , ( 7 , 9 ) } \left\{\left(1,5\right),\left(3,7\right),\left(7,9\right)\right\} { ( 1 , 5 ) , ( 3 , 7 ) , ( 7 , 9 ) }

Diketahui g ( x ) = 6 x + 5 2 x + 3 − 1 g\left(x\right)=\frac{6x+5}{2x+3}-1 g ( x ) = 2 x + 3 6 x + 5 − 1 . Invers fungsi g adalah ...

g − 1 ( x ) = − 3 x + 2 2 x − 4 ; x ≠ 2 g^{-1}\left(x\right)=\frac{-3x+2}{2x-4};\ x\ne2 g − 1 ( x ) = 2 x − 4 − 3 x + 2 ; x  = 2

g − 1 ( x ) = − 3 x + 4 2 x − 6 ; x ≠ 3 g^{-1}\left(x\right)=\frac{-3x+4}{2x-6};\ x\ne3 g − 1 ( x ) = 2 x − 6 − 3 x + 4 ; x  = 3

g − 1 ( x ) = − 3 x + 2 2 x − 6 ; x ≠ 3 g^{-1}\left(x\right)=\frac{-3x+2}{2x-6};\ x\ne3 g − 1 ( x ) = 2 x − 6 − 3 x + 2 ; x  = 3

g − 1 ( x ) = 3 x + 2 2 x − 6 ; x ≠ 3 g^{-1}\left(x\right)=\frac{3x+2}{2x-6};\ x\ne3 g − 1 ( x ) = 2 x − 6 3 x + 2 ; x  = 3

g − 1 ( x ) = 3 x + 2 2 x − 4 ; x ≠ 2 g^{-1}\left(x\right)=\frac{3x+2}{2x-4};\ x\ne2 g − 1 ( x ) = 2 x − 4 3 x + 2 ; x  = 2

Sebuah merk sepatu dijual dengan diskon berganda. Mula-mula diberikan diskon sehingga harga sepatu menjadi f ( x ) = 0 , 9 x f\left(x\right)=0,9x f ( x ) = 0 , 9 x . Kemudian, diskon kedua diberikan sehingga harga akhir sepatu ( g o f ) ( x ) = 0 , 72 x \left(g\ o\ f\right)\left(x\right)=0,72x ( g o f ) ( x ) = 0 , 7 2 x . Rumus g ( x ) g\left(x\right) g ( x ) adalah ....

g ( x ) = 0 , 8 x g\left(x\right)=0,8x g ( x ) = 0 , 8 x

g ( x ) = 0 , 6 x g\left(x\right)=0,6x g ( x ) = 0 , 6 x

g ( x ) = 0 , 7 x g\left(x\right)=0,7x g ( x ) = 0 , 7 x

g ( x ) = 0 , 9 x g\left(x\right)=0,9x g ( x ) = 0 , 9 x

g ( x ) = x g\left(x\right)=x g ( x ) = x

Jika f − 1 ( x ) = 3 x + 5 f^{-1}\left(x\right)=3x+5 f − 1 ( x ) = 3 x + 5 dan ( g o f ) − 1 ( x ) = x − 1 \left(g\ o\ f\right)^{-1}\left(x\right)=x-1 ( g o f ) − 1 ( x ) = x − 1 , invers fungsi g adalah ....

g − 1 ( x ) = x − 6 3 g^{-1}\left(x\right)=\frac{x-6}{3} g − 1 ( x ) = 3 x − 6

g − 1 ( x ) = x + 6 3 g^{-1}\left(x\right)=\frac{x+6}{3} g − 1 ( x ) = 3 x + 6

g − 1 ( x ) = x − 6 g^{-1}\left(x\right)=x-6 g − 1 ( x ) = x − 6

g − 1 ( x ) = 3 x + 6 g^{-1}\left(x\right)=3x+6 g − 1 ( x ) = 3 x + 6

g − 1 ( x ) = 3 x + 9 g^{-1}\left(x\right)=3x+9 g − 1 ( x ) = 3 x + 9

Diketahui g ( x ) = 3 x + 2 g\left(x\right)=3x+2 g ( x ) = 3 x + 2 dan ( f o g ) ( x ) = 3 x + 2 3 x + 1 ; x ≠ − 1 3 \left(f\ o\ g\right)\left(x\right)=\frac{3x+2}{3x+1};\ x\ne-\frac{1}{3} ( f o g ) ( x ) = 3 x + 1 3 x + 2 ; x  = − 3 1 . Rumus fungsi f ( x ) = . . . . f\left(x\right)=.... f ( x ) = . . . .

x x − 1 ; x ≠ 1 \frac{x}{x-1};\ x\ne1 x − 1 x ; x  = 1

x 3 x + 2 ; x ≠ − 2 3 \frac{x}{3x+2};\ x\ne-\frac{2}{3} 3 x + 2 x ; x  = − 3 2

x x + 2 ; x ≠ − 2 \frac{x}{x+2};\ x\ne-2 x + 2 x ; x  = − 2

3 x 3 x − 1 ; x ≠ 1 3 \frac{3x}{3x-1};\ x\ne\frac{1}{3} 3 x − 1 3 x ; x  = 3 1

3 x 3 x − 3 ; x ≠ 1 \frac{3x}{3x-3};\ x\ne1 3 x − 3 3 x ; x  = 1

fungsi dan komposisi

Authored by Ade Setiawandi

Mathematics

10th Grade

CCSS covered

Used 18+ times

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fungsi f ditentukan oleh $f\left(x\right)=\frac{2x+1}{x-3},\ x\ne3$ jika $f^{-1}$ invers dari f, maka $f^{-1}\left(x+1\right)=$ ...

$\frac{3x-1}{x-2},\ x\ne2$

$\frac{3x+1}{x-2},\ x\ \ne2$

$\frac{3x+2}{x-1},\ x\ne1$

$\frac{3x+2}{x+1},\ x\ne-1$

$\frac{3x+4}{x-1},\ x\ne1$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.BF.B.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika f(x) = x – 3 dan g (x) = 3 – 2x, maka $\left(f\ \circ\ g\right)^{-1}=$ adalah

$2x$

$3-\frac{1}{2}x$

$-\frac{1}{2}x$

$-2x$

$\frac{1}{2}x-3$

Tags

CCSS.HSF.BF.B.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika $f\left(x\right)=7x+1$ dan $g\left(x\right)=\frac{1}{2}x-5$ , maka $\left(f\ \circ\ g\right)^{-1}\left(x\right)$ untuk $x=-4$ adalah ...

$8\ \frac{4}{7}$

$11\ \frac{3}{7}$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

CCSS.HSF.BF.B.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui $f\left(x\right)=2x-2,\ g\left(x\right)=\sqrt{4-x},$ dan $h\left(x\right)=4x-x^2$ . Fungsi $\left(f\ \circ\ g\ \circ\ h\right)\left(x\right)=$ ...

$2x-6$

$2x-4$

$2x-2$

$2x+2$

$2x+4$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui $f\left(x\right)=\frac{x}{x-1}$
untuk $x\ne1$ . Fungsi invers $f\left(x\right)$ adalah ...

$\frac{x}{x+1}$

$\frac{x}{x-1}$

$\frac{x-1}{x}$

$\frac{1}{x-1}$

$\frac{1}{x+1}$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.BF.B.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika $f\left(x+2\right)=\frac{2x-3}{4x+1}$
dan $g\left(x\right)=\sqrt{\frac{4x+1}{5-x^2}},$ nilai dari $\left(2f-3g\right)\left(2\right)$ adalah ...

$-15$

$-9$

$-3$

$3$

$15$

Tags

CCSS.HSA.APR.D.7

CCSS.HSA.SSE.A.1

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika $g\left(x\right)=\ x^2-7$ dan $\left(g\ \circ\ f\right)\left(x\right)=4x^2+16x+9,\$ fungsi $f\left(x\right)$ adalah ...

$-3x+7$

$-2x-2$

$2x+4$

$2x+8$

$3x+11$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.REI.B.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika $p\left(3x-1\right)=9x+1$
dan $q\left(x^2+1\right)=2x^2-3,$ hasil dari $\left(p\ \circ\ q\right)\left(x\right)$ adalah ...

$3x-3$

$3x+11$

$6x-11$

$6x-3$

$6x+3$

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.B.3

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika $g\left(x\right)=x^2-2x$
dan $\left(g\ \circ\ f\right)\left(x\right)=x^2-10x+24$ fungsi $f\left(x\right)$ adalah ...

$6-x$

$4-x$

$x-6$

$x-4$

$x+4$

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.CED.A.1

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui $f\left(x\right)=x-4$ , $g\left(x\right)=2x+5$ dan $h\left(x\right)=1+\frac{1}{x}$ . Jika $\left(h^{-1}\ \circ\ g^{-1}\ \circ\ f^{-1}\right)\left(a\right)=2$ nila a adalah

$-4$

$-2$

$1$

$3$

$4$

Tags

CCSS.HSF.BF.B.4

CCSS.HSA.CED.A.1

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fungsi dan komposisi

Fungsi f ditentukan oleh f(x)=2x+1x−3, x≠3f\left(x\right)=\frac{2x+1}{x-3},\ x\ne3f(x)=x−32x+1​, x​=3 jika f−1f^{-1}f−1 invers dari f, maka f−1(x+1)=f^{-1}\left(x+1\right)=f−1(x+1)= ...

Jika f(x) = x – 3 dan g (x) = 3 – 2x, maka (f ∘ g)−1=\left(f\ \circ\ g\right)^{-1}=(f ∘ g)−1= adalah

Jika f(x)=7x+1f\left(x\right)=7x+1f(x)=7x+1 dan g(x)=12x−5g\left(x\right)=\frac{1}{2}x-5g(x)=21​x−5 , maka (f ∘ g)−1(x)\left(f\ \circ\ g\right)^{-1}\left(x\right)(f ∘ g)−1(x) untuk x=−4x=-4x=−4 adalah ...

Diketahui f(x)=2x−2, g(x)=4−x,f\left(x\right)=2x-2,\ g\left(x\right)=\sqrt{4-x},f(x)=2x−2, g(x)=4−x​, dan h(x)=4x−x2h\left(x\right)=4x-x^2h(x)=4x−x2 . Fungsi (f ∘ g ∘ h)(x)=\left(f\ \circ\ g\ \circ\ h\right)\left(x\right)=(f ∘ g ∘ h)(x)= ...

Diketahui f(x)=xx−1f\left(x\right)=\frac{x}{x-1}f(x)=x−1x​ untuk x≠1x\ne1x​=1 . Fungsi invers f(x)f\left(x\right)f(x) adalah ...

Jika f(x+2)=2x−34x+1f\left(x+2\right)=\frac{2x-3}{4x+1}f(x+2)=4x+12x−3​ dan g(x)=4x+15−x2,g\left(x\right)=\sqrt{\frac{4x+1}{5-x^2}},g(x)=5−x24x+1​​, nilai dari (2f−3g)(2)\left(2f-3g\right)\left(2\right)(2f−3g)(2) adalah ...

Jika g(x)= x2−7g\left(x\right)=\ x^2-7g(x)= x2−7 dan (g ∘ f)(x)=4x2+16x+9, \left(g\ \circ\ f\right)\left(x\right)=4x^2+16x+9,\ (g ∘ f)(x)=4x2+16x+9, fungsi f(x)f\left(x\right)f(x) adalah ...

Jika p(3x−1)=9x+1p\left(3x-1\right)=9x+1p(3x−1)=9x+1 dan q(x2+1)=2x2−3,q\left(x^2+1\right)=2x^2-3,q(x2+1)=2x2−3, hasil dari (p ∘ q)(x)\left(p\ \circ\ q\right)\left(x\right)(p ∘ q)(x) adalah ...

Jika g(x)=x2−2xg\left(x\right)=x^2-2xg(x)=x2−2x dan (g ∘ f)(x)=x2−10x+24\left(g\ \circ\ f\right)\left(x\right)=x^2-10x+24(g ∘ f)(x)=x2−10x+24 fungsi f(x)f\left(x\right)f(x) adalah ...

Diketahui f(x)=x−4f\left(x\right)=x-4f(x)=x−4 , g(x)=2x+5g\left(x\right)=2x+5g(x)=2x+5 dan h(x)=1+1xh\left(x\right)=1+\frac{1}{x}h(x)=1+x1​ . Jika (h−1 ∘ g−1 ∘ f−1)(a)=2\left(h^{-1}\ \circ\ g^{-1}\ \circ\ f^{-1}\right)\left(a\right)=2(h−1 ∘ g−1 ∘ f−1)(a)=2 nila a adalah

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Fungsi f ditentukan oleh $f\left(x\right)=\frac{2x+1}{x-3},\ x\ne3$ jika $f^{-1}$ invers dari f, maka $f^{-1}\left(x+1\right)=$ ...

Jika f(x) = x – 3 dan g (x) = 3 – 2x, maka $\left(f\ \circ\ g\right)^{-1}=$ adalah

Jika $f\left(x\right)=7x+1$ dan $g\left(x\right)=\frac{1}{2}x-5$ , maka $\left(f\ \circ\ g\right)^{-1}\left(x\right)$ untuk $x=-4$ adalah ...

Diketahui $f\left(x\right)=2x-2,\ g\left(x\right)=\sqrt{4-x},$ dan $h\left(x\right)=4x-x^2$ . Fungsi $\left(f\ \circ\ g\ \circ\ h\right)\left(x\right)=$ ...

Diketahui $f\left(x\right)=\frac{x}{x-1}$
untuk $x\ne1$ . Fungsi invers $f\left(x\right)$ adalah ...

Jika $f\left(x+2\right)=\frac{2x-3}{4x+1}$
dan $g\left(x\right)=\sqrt{\frac{4x+1}{5-x^2}},$ nilai dari $\left(2f-3g\right)\left(2\right)$ adalah ...

Jika $g\left(x\right)=\ x^2-7$ dan $\left(g\ \circ\ f\right)\left(x\right)=4x^2+16x+9,\$ fungsi $f\left(x\right)$ adalah ...

Jika $p\left(3x-1\right)=9x+1$
dan $q\left(x^2+1\right)=2x^2-3,$ hasil dari $\left(p\ \circ\ q\right)\left(x\right)$ adalah ...

Jika $g\left(x\right)=x^2-2x$
dan $\left(g\ \circ\ f\right)\left(x\right)=x^2-10x+24$ fungsi $f\left(x\right)$ adalah ...

Diketahui $f\left(x\right)=x-4$ , $g\left(x\right)=2x+5$ dan $h\left(x\right)=1+\frac{1}{x}$ . Jika $\left(h^{-1}\ \circ\ g^{-1}\ \circ\ f^{-1}\right)\left(a\right)=2$ nila a adalah