Solve Quadratic Equations by Factoring

Set  $x+8=0$  and $x-2=0$  

Nothing the solution is  $x=8$  and  $x=-2$  

Multiply  $\left(x+8\right)\left(x-2\right)$  

Choose  $x+8$  or  $x-2$  and write a musical about them

 $x=-2$  or  $x=-11$  

 $x=2$  or  $x=-11$  

 $x=2$  or  $x=11$  

 $x=-2$  or  $x=11$  

 $x=-\frac{7}{3}$  or  $x=4$  

 $x=-\frac{7}{3}$  or  $x=-4$  

 $x=\frac{7}{3}$  or  $x=4$  

 $x=\frac{7}{3}$  or  $x=-4$  

 $\left(x-4\right)\left(x+5\right)=0$  

 $\left(x+20\right)\left(x-9\right)=0$  

 $\left(x-4\right)\left(x-5\right)=0$  

 $\left(x+4\right)\left(x+5\right)=0$  

x = - 4 and x = - 5

x = 20 and x = - 9

x = 4 and x = 5

x = - 4 and x = 5

x = - 5 or x = - 7

x = 5 or x = 7

x = - 35 or x = - 1

x = - 9 or x = - 4

x = -1

x = -1 or x = 1

x = 1

x = -2 or x = 5

 $\left(2x+1\right)\left(2x+1\right)=0$  

 $\left(2x-1\right)\left(2x+1\right)$  

 $\left(2x-1\right)\left(2x-1\right)$  

 $\left(4x+1\right)\left(1x+1\right)$  

 $x=\frac{1}{2}or\ x=-\frac{1}{2}$  

 $x=-\frac{1}{2}and\ x=-\frac{1}{2}$  

 $x=\frac{1}{2\ }and\ x=\frac{1}{2}$  

 $x=\frac{1}{4}or\ x=1$