Diketahui Δ A B C \Delta ABC Δ A B C , panjang sisi BC = 4 cm, Besar ∠ A = 120 ° , ∠ B = 30 ° \angle A=120\degree,\angle B=30\degree ∠ A = 1 2 0 ° , ∠ B = 3 0 ° panjang sisi AB = ....cm

4 3 3 \frac{4}{3}\sqrt{3} 3 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 2\sqrt{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 4 3 \frac{3}{4}\sqrt{3} 4 3 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 4 2 \frac{3}{4}\sqrt{2} 4 3 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Diketahui segitiga PQR, Besar sudut P adalah 30 ° 30\degree 3 0 ° , Panjang sisi PR = 9 cm, Panjang sisi PQ = 9 3 9\sqrt{3} 9 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cm. Panjang sisi QR = ...cm

9 2 9\sqrt{2} 9 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

9 3 9\sqrt{3} 9 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 2 6\sqrt{2} 6 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 3 6\sqrt{3} 6 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Diketahui A dan B adalah titik-titik ujung terowongan yang dilihat dari C dengan ∠ A C B = 45 ° \angle ACB=45\degree ∠ A C B = 4 5 ° . Jika jarak CB = p meter dan CA = 2 p 2 2p\sqrt{2} 2 p 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> meter, maka panjang terowongan adalah....meter

p 5 p\sqrt{5} p 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

p 17 p\sqrt{17} p 1 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 p 2 3p\sqrt{2} 3 p 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Sebuah kapal berlayar dari pelabuhan A ke pelabuhan B sejauh 60 mil dengan arah 040 ° 040\degree 0 4 0 ° dari A, kemudian berputar haluan ke pelabuhan C sejauh 90 mil dengan arah 160 ° 160\degree 1 6 0 ° dari pelabuhan B. Jarak pelabuhan A dan C adalah.... mil

30 7 30\sqrt{7} 3 0 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

30 2 30\sqrt{2} 3 0 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

30 5 30\sqrt{5} 3 0 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

30 6 30\sqrt{6} 3 0 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

30 3 30\sqrt{3} 3 0 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Luas segitiga

Authored by Siti Rohmah

Mathematics

10th Grade

CCSS covered

Used 11+ times

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Perhatikan gambar berikut.
Panjang sisi BC =... cm

$5\sqrt{6}$

$\frac{10\sqrt{6}}{3}$

$5\sqrt{2}$

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

Diketahui $\Delta ABC$ , panjang sisi BC = 4 cm, Besar $\angle A=120\degree,\angle B=30\degree$ panjang sisi AB = ....cm

$2\sqrt{2}$

$\frac{4}{3}\sqrt{3}$

$\frac{3}{4}\sqrt{3}$

$\frac{3}{4}\sqrt{2}$

$\sqrt{3}$

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui segitiga QRS, panjang sisi QS = 9 cm, panjang sisi QR = $3\sqrt{3}$ cm, Besar $\angle R\ =\ 60\degree$ , Besar $\angle S=...\degree$

120

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui segitiga PQR, Besar sudut P adalah $30\degree$ , Panjang sisi PR = 9 cm, Panjang sisi PQ = $9\sqrt{3}$ cm. Panjang sisi QR = ...cm

$9\sqrt{2}$

$9\sqrt{3}$

$6\sqrt{2}$

$6\sqrt{3}$

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diketahui A dan B adalah titik-titik ujung terowongan yang dilihat dari C dengan $\angle ACB=45\degree$ . Jika jarak CB = p meter dan CA = $2p\sqrt{2}$ meter, maka panjang terowongan adalah....meter

$p\sqrt{5}$

$p\sqrt{17}$

$3p\sqrt{2}$

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Sebuah kapal berlayar dari pelabuhan A ke pelabuhan B sejauh 60 mil dengan arah $040\degree$ dari A, kemudian berputar haluan ke pelabuhan C sejauh 90 mil dengan arah $160\degree$ dari pelabuhan B. Jarak pelabuhan A dan C adalah.... mil

$30\sqrt{2}$

$30\sqrt{5}$

$30\sqrt{7}$

$30\sqrt{6}$

$30\sqrt{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Tanah Pak Yanto berbentuk segitiga sembarang seperti yang terlihat pada gambar. Luas tanah pak Yanto adalah... $m^2$

$72\sqrt{2}$

$72\sqrt{3}$

144

$\frac{\sqrt{106}}{4}$

Tags

CCSS.HSG.SRT.D.9

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui sebuah jajargenjang ABCD. Panjang AB = 12 cm, panjang sisi BC = 8 cm. Jika besar $\angle ABC=135\degree$ maka Luas jajargenjang ABCD = .... $cm^2$

$48\sqrt{2}$

$48\sqrt{3}$

$96\sqrt{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui segitiga KLM, panjang sisi Kl = 10 cm, LM = 14 cm dan KM = 16 cm. Luas segitiga KLM = ... $cm^2$

$40\sqrt{2}$

$40\sqrt{3}$

$40\sqrt{6}$

$40\sqrt{5}$

10.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Pada sebuah lingkaran dibuat segi-12 beraturan. Jika jari-jari lingkaran adalah 10 cm, Luas segi-12 beraturan adalah....cm²

150

$150\sqrt{3}$

300

$300\sqrt{3}$

$300\sqrt{2}$

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Luas segitiga

Perhatikan gambar berikut.Panjang sisi BC =... cm

Diketahui ΔABC\Delta ABCΔABC , panjang sisi BC = 4 cm, Besar ∠A=120°,∠B=30°\angle A=120\degree,\angle B=30\degree∠A=120°,∠B=30° panjang sisi AB = ....cm

Diketahui segitiga QRS, panjang sisi QS = 9 cm, panjang sisi QR = 333\sqrt{3}33​ cm, Besar ∠R = 60°\angle R\ =\ 60\degree∠R = 60° , Besar ∠S=...°\angle S=...\degree∠S=...°

Diketahui segitiga PQR, Besar sudut P adalah 30°30\degree30° , Panjang sisi PR = 9 cm, Panjang sisi PQ = 939\sqrt{3}93​ cm. Panjang sisi QR = ...cm

Diketahui A dan B adalah titik-titik ujung terowongan yang dilihat dari C dengan ∠ACB=45°\angle ACB=45\degree∠ACB=45° . Jika jarak CB = p meter dan CA = 2p22p\sqrt{2}2p2​ meter, maka panjang terowongan adalah....meter

Sebuah kapal berlayar dari pelabuhan A ke pelabuhan B sejauh 60 mil dengan arah 040°040\degree040° dari A, kemudian berputar haluan ke pelabuhan C sejauh 90 mil dengan arah 160°160\degree160° dari pelabuhan B. Jarak pelabuhan A dan C adalah.... mil

Tanah Pak Yanto berbentuk segitiga sembarang seperti yang terlihat pada gambar. Luas tanah pak Yanto adalah... m2m^2m2

Diketahui sebuah jajargenjang ABCD. Panjang AB = 12 cm, panjang sisi BC = 8 cm. Jika besar ∠ABC=135°\angle ABC=135\degree∠ABC=135° maka Luas jajargenjang ABCD = .... cm2cm^2cm2

Diketahui segitiga KLM, panjang sisi Kl = 10 cm, LM = 14 cm dan KM = 16 cm. Luas segitiga KLM = ... cm2cm^2cm2

Pada sebuah lingkaran dibuat segi-12 beraturan. Jika jari-jari lingkaran adalah 10 cm, Luas segi-12 beraturan adalah....cm2

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Perhatikan gambar berikut.
Panjang sisi BC =... cm

Diketahui $\Delta ABC$ , panjang sisi BC = 4 cm, Besar $\angle A=120\degree,\angle B=30\degree$ panjang sisi AB = ....cm

Diketahui segitiga QRS, panjang sisi QS = 9 cm, panjang sisi QR = $3\sqrt{3}$ cm, Besar $\angle R\ =\ 60\degree$ , Besar $\angle S=...\degree$

Diketahui segitiga PQR, Besar sudut P adalah $30\degree$ , Panjang sisi PR = 9 cm, Panjang sisi PQ = $9\sqrt{3}$ cm. Panjang sisi QR = ...cm

Diketahui A dan B adalah titik-titik ujung terowongan yang dilihat dari C dengan $\angle ACB=45\degree$ . Jika jarak CB = p meter dan CA = $2p\sqrt{2}$ meter, maka panjang terowongan adalah....meter

Sebuah kapal berlayar dari pelabuhan A ke pelabuhan B sejauh 60 mil dengan arah $040\degree$ dari A, kemudian berputar haluan ke pelabuhan C sejauh 90 mil dengan arah $160\degree$ dari pelabuhan B. Jarak pelabuhan A dan C adalah.... mil

Tanah Pak Yanto berbentuk segitiga sembarang seperti yang terlihat pada gambar. Luas tanah pak Yanto adalah... $m^2$

Diketahui sebuah jajargenjang ABCD. Panjang AB = 12 cm, panjang sisi BC = 8 cm. Jika besar $\angle ABC=135\degree$ maka Luas jajargenjang ABCD = .... $cm^2$

Diketahui segitiga KLM, panjang sisi Kl = 10 cm, LM = 14 cm dan KM = 16 cm. Luas segitiga KLM = ... $cm^2$

Pada sebuah lingkaran dibuat segi-12 beraturan. Jika jari-jari lingkaran adalah 10 cm, Luas segi-12 beraturan adalah....cm²