Jumlah dan Selisih Trigonometri

Jumlah dan Selisih Trigonometri

10th Grade

10 Qs

quiz-placeholder

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Jumlah dan Selisih Trigonometri

Jumlah dan Selisih Trigonometri

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
HSF.TF.C.9

Standards-aligned

Created by

Eka Primayanti

Used 105+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 cos85°cos55° + sin85°sin55° = . . .\cos85\degree\cos55\degree\ +\ \sin85\degree\sin55\degree\ =\ .\ .\ .  

 00  

 11  

 12\frac{1}{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 tan75°tan15°1+tan75°tan15°= . . .\frac{\tan75\degree-\tan15\degree}{1+\tan75\degree\tan15\degree}=\ .\ .\ .  

 00  

 3\sqrt{3}  

 133\frac{1}{3}\sqrt{3}  

 11  

tidak terdefenisi

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diberikan dua buah sudut A dan B dengan nilai sinus masing-masing adalah  sinA=45\sin A=\frac{4}{5}  dan  sinB=1213\sin B=\frac{12}{13} . Sudut A adalah sudut tumpul sedangkan sudut B adalah sudut lancip. Nilai dari  sin(AB)\sin\left(A-B\right)  adalah...

 5665\frac{56}{65}  

 5665-\frac{56}{65}  

 1665\frac{16}{65}  

 1665-\frac{16}{65}  

 6556\frac{65}{56}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 cos105°+cos15°=...\cos105\degree+\cos15\degree=...  

 12\frac{1}{2}  

 2\sqrt{2}  

1

 122\frac{1}{2}\sqrt{2}  

 122-\frac{1}{2}\sqrt{2}  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Nilai dari  cos15°\cos15\degree  adalah ...

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(-\sqrt{2}-\sqrt{6}\right)  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 12(62)\frac{1}{2}\left(\sqrt{6}-\sqrt{2}\right)  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 cos 100°+cos40°sin 130°sin 10°\frac{\cos\ 100\degree+\cos40\degree}{\sin\ 130\degree-\sin\ 10\degree}  = ...

 3\sqrt{3}  

-1

0

1

 123\frac{1}{2}\sqrt{3}  

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 sin(105°)=...\sin\left(105\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

Tags

CCSS.HSF.TF.C.9

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