Multiply Complex Numbers (answers in (a + bi) form)

Authored by C. Bowman

Mathematics

9th - 12th Grade

CCSS covered

Used 15+ times

Multiply Complex Numbers (answers in (a + bi) form)

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OPEN ENDED QUESTION

3 mins • Ungraded

$-3i\left(9-6i\right)$

Evaluate responses using AI:

OFF

Tags

CCSS.HSN.CN.A.2

OPEN ENDED QUESTION

3 mins • Ungraded

$-11i\left(3+9i\right)$

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OFF

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CCSS.HSN.CN.A.2

OPEN ENDED QUESTION

3 mins • Ungraded

$\left(2+4i\right)\left(3+3i\right)$

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CCSS.HSN.CN.C.8

OPEN ENDED QUESTION

3 mins • Ungraded

$\left(-3-7i\right)\left(-12-2i\right)$

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OFF

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CCSS.HSN.CN.C.8

OPEN ENDED QUESTION

3 mins • Ungraded

$\left(15+3i\right)\left(4-15i\right)$

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OFF

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CCSS.HSN.CN.C.8

OPEN ENDED QUESTION

3 mins • Ungraded

$\left(7-3i\right)\left(7+3i\right)$

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OFF

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CCSS.HSN.CN.C.8

OPEN ENDED QUESTION

3 mins • Ungraded

$i\left(4+3i\right)$

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CCSS.HSN.CN.A.2

OPEN ENDED QUESTION

3 mins • Ungraded

$\left(3+2i\right)^2$

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CCSS.HSN.CN.C.8

OPEN ENDED QUESTION

3 mins • Ungraded

$-\left(2+2i\right)^2$

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CCSS.HSN.CN.C.8

10.

OPEN ENDED QUESTION

5 mins • Ungraded

Explain what this student did wrong:
$\left(3+6i\right)\left(2-5i\right)$
$6-30i$

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OFF

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CCSS.HSN.CN.A.2

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Multiply Complex Numbers (answers in (a + bi) form)

−3i(9−6i)-3i\left(9-6i\right)−3i(9−6i)

−11i(3+9i)-11i\left(3+9i\right)−11i(3+9i)

(2+4i)(3+3i)\left(2+4i\right)\left(3+3i\right)(2+4i)(3+3i)

(−3−7i)(−12−2i)\left(-3-7i\right)\left(-12-2i\right)(−3−7i)(−12−2i)

(15+3i)(4−15i)\left(15+3i\right)\left(4-15i\right)(15+3i)(4−15i)

(7−3i)(7+3i)\left(7-3i\right)\left(7+3i\right)(7−3i)(7+3i)

i(4+3i)i\left(4+3i\right)i(4+3i)

(3+2i)2\left(3+2i\right)^2(3+2i)2

−(2+2i)2-\left(2+2i\right)^2−(2+2i)2

Explain what this student did wrong: (3+6i)(2−5i)\left(3+6i\right)\left(2-5i\right)(3+6i)(2−5i) 6−30i6-30i6−30i

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$-3i\left(9-6i\right)$

$-11i\left(3+9i\right)$

$\left(2+4i\right)\left(3+3i\right)$

$\left(-3-7i\right)\left(-12-2i\right)$

$\left(15+3i\right)\left(4-15i\right)$

$\left(7-3i\right)\left(7+3i\right)$

$i\left(4+3i\right)$

$\left(3+2i\right)^2$

$-\left(2+2i\right)^2$

Explain what this student did wrong:
$\left(3+6i\right)\left(2-5i\right)$
$6-30i$