Solving Quadratics: All 3 Methods-Factoring, Radicals, Formu

Determine the values of a, b, and c for the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

What should you do first in solving this equation?

x² + 6x - 13 = 3

• Factor

• Write down: a = 1, b = 6, c = -13

• Subtract 3 from both sides.

• Add 3 to both sides.

Tags

CCSS.HSA-REI.B.4B

How many solutions does the equation 4x² + 4x + 1 = 0 have?

• 0
• 1
• 2
• More than 2

Tags

CCSS.HSA-REI.B.4B

If the discriminant is zero you will have

• no real solutions
• two real solutions
• 1 real solution
• 1 imaginary solution

Tags

CCSS.HSA-REI.B.4B

b² - 4ac would equal: y = 2x² -x -3

• 25
• -23
• -25
• 0

Tags

CCSS.HSA-REI.B.4B

Solve Using the Quadratic Formula
 x² + 4x - 40 = -8

• -10 & -4
• -4 & 10
• -8 & 4
• 8 & -4

Tags

CCSS.HSA-REI.B.4B

REVIEW: What is the degree of every Quadratic Equation?

• 1

• 2

• 3

• 4

Solve the equation using the zero product property.
3x ( 2x - 4) = 0

• x = -1/3 or x = -2
• x = 0 or x = 2
• x = 0 or x = -2
• x = -1/3 or x = 2

Tags

CCSS.HSA-REI.B.4B

Solve the equation by factoring.
x² + 13x + 40 = 0

• -8, 5
• -40, -1
• 5, 8
• -8, -5

Tags

CCSS.HSA-REI.B.4B

What are the factors AND solutions of x² + 2x – 3 = 0

• (x - 2)(x + 1); x=2, x=-1
• (x + 1)(x - 3); x=-1, x=3
• (x + 2)(x - 1); x=-2, x=1
• (x - 1)(x + 3); x=1, x=-3

Tags

CCSS.HSA-REI.B.4B