Review #3 - Analyzing Derivatives/Particle Motion

Review #3 - Analyzing Derivatives/Particle Motion

11th - 12th Grade

15 Qs

quiz-placeholder

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Review #3 - Analyzing Derivatives/Particle Motion

Review #3 - Analyzing Derivatives/Particle Motion

Assessment

Quiz

Mathematics

11th - 12th Grade

Practice Problem

Medium

CCSS
HSF.IF.B.4, HSN.VM.A.3, HSF.LE.B.5

+6

Standards-aligned

Created by

SAMI GARROUTTE

Used 55+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A particle's speed is decreasing if

it's acceleration is positive
it's velocity is positive
it's velocity and acceleration have the same sign
it's velocity and acceleration have different signs

Tags

CCSS.HSN.VM.A.3

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

v(t)>0 means

the particle is moving to the right
the particle is moving to the left
the particle has positive position
the particle is at rest

Tags

CCSS.HSF.LE.B.5

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

s(t) = t2 - 20
Find the average velocity from t = 3 to t = 5.

2
4
6
8

Tags

CCSS.8.F.B.4

CCSS.HSF.IF.B.6

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

An objects distance from its starting point at time t is given by the equation
s(t) = t3 - 6t2  - 4. 
What is the speed of
the object when its acceleration is 0? 

2
-24
22
44

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.1

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

A bug begins to crawl up a vertical wire at time t = 0.  The velocity v of the bug at time t, 0 < t < 8, is given by the function whose graph is shown behind this text. At what value of t does the bug change direction

2
4
6.5
7

Tags

CCSS.HSF.IF.B.4

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Set up, but do not solve: If the position of Particle Bill is given by s(t) = x3 +2x - 7, how would you find when Bill is at rest?

x3 +2x - 7 = 0

3x2 + 2 = 0

6x = 0

No work necessary. At rest when t = -7.

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What are the intervals of the graph increasing for f(x) = 2x4- 4x2 + 1

(-1,0)

(0,1)

(-∞,-1) \cup (1,∞)

(-1, 0) \cup (1, \infty )

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