Solving Quadratic Equations by Factoring and Square Root

Solve by factoring.  $x^2+5x-36=0$  

• -9, 4

•  $\pm6$  

• -12, 3

• 2, -18

 $Solve\ by\ factoring.\ x^2-x\ -56=0$  

• 56, -1

• -14, 4

• 2, -28

• -7, 8

8x(x+1)(x-10)=0

• -8, -1, 10

• $\frac{1}{8},\ 10$

• 0, -1, 10

• no real solution

 $Solve\ by\ factoring\ x^2-10x=-16$  

• 2, 8

• 4, -4

• -1, 16

• no real solution

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Which one of the following is the standard form of a quadratic equation?

• y = mx + b

• $y=mc^2$

• $a^2+b^2=c^2$

• $ax^2+bx+c=0$

 $Solve\ by\ the\ square\ root\ property.\ \ x^2=15$  

• 3, 5

•  $\pm\sqrt{15}$  

•  $\pm15$  

•  $\pm3\sqrt{5}$  

 $-4x^2=64$  

•  $\pm21$  

•  $\pm32$  

•  $\pm256$  

•  no real solution

 $x^2-5=31$  

•  $\pm6$  

•  $\pm36$  

•  $\pm26$  

• no real solution

 $\left(x-5\right)^2=21$  

•  $\pm\sqrt{21}$  

•  $5\pm\sqrt{21}$  

•  $\pm\sqrt{26}$  

•  $5\pm\sqrt{26}$   

True or False. When solving quadratic equations using the square root property, the first step is to isolate the squared expression.

• True

• False