D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ !

( 1 , 8 , 11 ) \left(1,8,11\right) ( 1 , 8 , 1 1 )

( 3 , 8 , 11 ) \left(3,8,11\right) ( 3 , 8 , 1 1 )

( 3 , − 8 , 11 ) \left(3,-8,11\right) ( 3 , − 8 , 1 1 )

( 1 , − 8 , 11 ) \left(1,-8,11\right) ( 1 , − 8 , 1 1 )

( − 1 , 8 , 11 ) \left(-1,8,11\right) ( − 1 , 8 , 1 1 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k 𝑏 = − 𝑖 + 3 𝑗 + 7 𝑘 d a n 𝑐 = 5 𝑖 − 2 𝑗 − 𝑘 𝑏=−𝑖+3𝑗+7𝑘\ dan\ 𝑐=5𝑖−2𝑗−𝑘 b = − i + 3 j + 7 k d a n c = 5 i − 2 j − k T e n t u k a n a ⃗ − c ⃗ ! Tentukan\ a⃗-c⃗! T e n t u k a n a ⃗ − c ⃗ !

( − 3 , 7 , 5 ) (-3,7,5) ( − 3 , 7 , 5 )

( − 3 , 7 , − 5 ) (-3,7,-5) ( − 3 , 7 , − 5 )

( 3 , 7 , 5 ) (3,7,5) ( 3 , 7 , 5 )

( 7 , 7 , 3 ) \left(7,7,3\right) ( 7 , 7 , 3 )

( − 7 , 7 , 3 ) \left(-7,7,3\right) ( − 7 , 7 , 3 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n 2 a ⃗ − c ⃗ ! c⃗=5i-2j-k\ Tentukan\ 2a⃗-c⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n 2 a ⃗ − c ⃗ !

( 5 , 7 , 1 ) \left(5,7,1\right) ( 5 , 7 , 1 )

( − 5 , 7 , 1 ) \left(-5,7,1\right) ( − 5 , 7 , 1 )

( 5 , − 7 , 1 ) \left(5,-7,1\right) ( 5 , − 7 , 1 )

( 5 , 7 , − 1 ) \left(5,7,-1\right) ( 5 , 7 , − 1 )

( − 5 , − 7 , − 1 ) \left(-5,-7,-1\right) ( − 5 , − 7 , − 1 )

D i k e t a h u i t i t i k A ( 5 , − 1 , 2 ) d a n Diketahui\ titik\ A(5,-1,2)\ dan\ D i k e t a h u i t i t i k A ( 5 , − 1 , 2 ) d a n B ( 2 , 2 , − 1 ) . B(2,2,-1).\ B ( 2 , 2 , − 1 ) . Jika titik C terletak pada ruas garis AB sedemikian sehingga A C : C B = 1 : 2. T e n t u k a n k o o r d i n a t AC:CB=1:2.Tentukan\ koordinat\ A C : C B = 1 : 2 . T e n t u k a n k o o r d i n a t t i t i k C ! titik\ C! t i t i k C !

( 4 , 0 , 1 ) \left(4,0,1\right) ( 4 , 0 , 1 )

( 4 , 1 , 1 ) \left(4,1,1\right) ( 4 , 1 , 1 )

( 4 , 0 , 0 ) \left(4,0,0\right) ( 4 , 0 , 0 )

( 12 , 0 , 3 ) \left(12,0,3\right) ( 1 2 , 0 , 3 )

( 12 , 0 , 0 ) \left(12,0,0\right) ( 1 2 , 0 , 0 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k , Diketahui\ a⃗=2i+5j+4k,\ D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k , b ⃗ = − i + 3 j + 7 k b⃗=-i+3j+7k b ⃗ = − i + 3 j + 7 k d a n 𝑐 = 5 𝑖 − 2 𝑗 − 𝑘 T e n t u k a n 𝑐 − 𝑏 ! dan\ 𝑐=5𝑖−2𝑗−𝑘\ Tentukan\ 𝑐−𝑏! d a n c = 5 i − 2 j − k T e n t u k a n c − b !

( 6 , − 5 , − 8 ) \left(6,-5,-8\right) ( 6 , − 5 , − 8 )

( 6 , 5 , 8 ) \left(6,5,8\right) ( 6 , 5 , 8 )

( − 6 , − 5 , − 8 ) \left(-6,-5,-8\right) ( − 6 , − 5 , − 8 )

( 6 , − 5 , 8 ) \left(6,-5,8\right) ( 6 , − 5 , 8 )

( 6 , 5 , − 8 ) \left(6,5,-8\right) ( 6 , 5 , − 8 )

Diketahui a → = 4 i − 5 j + 3 k \overrightarrow{a}=4i-5j+3k a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 4 i − 5 j + 3 k , b → = 2 i + 2 j + k \overrightarrow{b}=2i+2j+k b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 i + 2 j + k , dan c → = 4 i + j − k \overrightarrow{c}=4i+j-k c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 4 i + j − k . Jika p → = a → − 2 b → + 3 c → \overrightarrow{p}=\overrightarrow{a}-2\overrightarrow{b}+3\overrightarrow{c} p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 2 b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 3 c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> panjang vektor p → \overrightarrow{p} p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah ....

2 46 2\sqrt{46} 2 4 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 46 3\sqrt{46} 3 4 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

46 \sqrt{46} 4 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

23 \sqrt{23} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 23 2\sqrt{23} 2 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Vektor

Quiz

•

Mathematics

•

10th Grade

•

Practice Problem

•

Medium

•

CCSS

HSN-VM.B.4A, HSN.VM.A.2, HSN-VM.B.4C

+1

Standards-aligned

nurlaela rahmawati

Used 153+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 12 pts

$Diketahui\ a⃗=2i+5j+4k$
$b⃗=-i+3j+7k\ dan$
$c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!$

$\left(3,8,11\right)$

$\left(3,-8,11\right)$

$\left(1,-8,11\right)$

$\left(-1,8,11\right)$

$\left(1,8,11\right)$

$Diketahui\ ׀a⃗׀=8,׀b⃗׀=2$
$dan\ ϴ=45^o.Tentukan\ a⃗.b⃗!$

$18√2$

$16√2$

$16√3$

$8√2$

$8√3$

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$Diketahui\ a⃗=i+2j+2k,$ $b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!$

$-9$

$9$

$1$

$-1$

$-6$

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

|a| = 11

|a| = 13

|a| = 15

|a| = 17

|a| = 19

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$Diketahui\ u⃗=2i+j-2k\ dan$
$v⃗=i+3j+k.Tentukan\ panjang\$
$proyeksi\ orthogonal\ u⃗\ pada\ v⃗.$

$1/√11$

$2/√11$

$3/√11$

$4/√11$

$5/√11$

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui vector a = 4i 2j + 2k dan vector b = 2i – 6j + 4k. Proyeksi vector orthogonal vector a pada vector b adalah

i - j + k

i - 3j + 2k

i - 4j + 4k

2i - j + k

6i - 8j + 6k

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

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Vektor

20 questions

$Diketahui\ a⃗=2i+5j+4k$
$b⃗=-i+3j+7k\ dan$
$c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!$

$Diketahui\ ׀a⃗׀=8,׀b⃗׀=2$
$dan\ ϴ=45^o.Tentukan\ a⃗.b⃗!$

$Diketahui\ a⃗=i+2j+2k,$ $b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!$

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

$Diketahui\ u⃗=2i+j-2k\ dan$
$v⃗=i+3j+k.Tentukan\ panjang\$
$proyeksi\ orthogonal\ u⃗\ pada\ v⃗.$

Diketahui vector a = 4i 2j + 2k dan vector b = 2i – 6j + 4k. Proyeksi vector orthogonal vector a pada vector b adalah

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Seorang anak berjalan lurus 2 meter ke barat, kemudian belok ke selatan sejauh 6 meter, dan belok lagi ke timur sejauh 10 meter. Perpindahan yang dilakukan anak tersebut dari posisi awal ….

Diketahui vektor pada R3 berikut:
a = 8 i - 4 j + 3 k
b = 3 i - 2 j
c = - i - 5 j + 7 k

Hasil dari 2a - b + 3c adalah ...

Diberikan vektor $\overrightarrow{a}$ , $\overrightarrow{b}$ dan $\overrightarrow{c}$ . Tentukan vektor resultan $\overleftarrow{a}$ + $\overrightarrow{b}$ - $\overrightarrow{c}$ dengan metode poligon

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Vektor

20 questions

Diketahui a⃗=2i+5j+4kDiketahui\ a⃗=2i+5j+4kDiketahui a⃗=2i+5j+4k b⃗=−i+3j+7k danb⃗=-i+3j+7k\ danb⃗=−i+3j+7k dan c⃗=5i−2j−k Tentukan a⃗+b⃗!c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!c⃗=5i−2j−k Tentukan a⃗+b⃗!

Diketahui ׀a⃗׀=8,׀b⃗׀=2Diketahui\ ׀a⃗׀=8,׀b⃗׀=2Diketahui ׀a⃗׀=8,׀b⃗׀=2 dan ϴ=45o.Tentukan a⃗.b⃗!dan\ ϴ=45^o.Tentukan\ a⃗.b⃗!dan ϴ=45o.Tentukan a⃗.b⃗!

Diketahui a⃗=i+2j+2k,Diketahui\ a⃗=i+2j+2k,Diketahui a⃗=i+2j+2k, b⃗=−3i−j−2k. Tentukan a⃗.b⃗!b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!b⃗=−3i−j−2k. Tentukan a⃗.b⃗!

Jika vektor a = 12 i + 5 k . ﻿Maka panjang vektor a adalah ...

Diketahui u⃗=2i+j−2k danDiketahui\ u⃗=2i+j-2k\ danDiketahui u⃗=2i+j−2k dan v⃗=i+3j+k.Tentukan panjang v⃗=i+3j+k.Tentukan\ panjang\ v⃗=i+3j+k.Tentukan panjang proyeksi orthogonal u⃗ pada v⃗.proyeksi\ orthogonal\ u⃗\ pada\ v⃗.proyeksi orthogonal u⃗ pada v⃗.

Diketahui vector a = 4i 2j + 2k dan vector b = 2i – 6j + 4k. Proyeksi vector orthogonal vector a pada vector b adalah

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Seorang anak berjalan lurus 2 meter ke barat, kemudian belok ke selatan sejauh 6 meter, dan belok lagi ke timur sejauh 10 meter. Perpindahan yang dilakukan anak tersebut dari posisi awal ….

Diketahui vektor pada R3 berikut: a = 8 i - 4 j + 3 kb = 3 i - 2 jc = - i - 5 j + 7 kHasil dari 2a - b + 3c adalah ...

Diberikan vektor a→\overrightarrow{a}a , b→\overrightarrow{b}b dan c→\overrightarrow{c}c . Tentukan vektor resultan a←\overleftarrow{a}a + b→\overrightarrow{b}b - c→\overrightarrow{c}c dengan metode poligon

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$Diketahui\ a⃗=2i+5j+4k$
$b⃗=-i+3j+7k\ dan$
$c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!$

$Diketahui\ ׀a⃗׀=8,׀b⃗׀=2$
$dan\ ϴ=45^o.Tentukan\ a⃗.b⃗!$

$Diketahui\ a⃗=i+2j+2k,$ $b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!$

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

$Diketahui\ u⃗=2i+j-2k\ dan$
$v⃗=i+3j+k.Tentukan\ panjang\$
$proyeksi\ orthogonal\ u⃗\ pada\ v⃗.$

Diketahui vektor pada R3 berikut:
a = 8 i - 4 j + 3 k
b = 3 i - 2 j
c = - i - 5 j + 7 k

Hasil dari 2a - b + 3c adalah ...

Diberikan vektor $\overrightarrow{a}$ , $\overrightarrow{b}$ dan $\overrightarrow{c}$ . Tentukan vektor resultan $\overleftarrow{a}$ + $\overrightarrow{b}$ - $\overrightarrow{c}$ dengan metode poligon