5/12: Continuity in Piecewise Functions

5/12: Continuity in Piecewise Functions

11th Grade

8 Qs

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5/12: Continuity in Piecewise Functions

5/12: Continuity in Piecewise Functions

Assessment

Quiz

Mathematics

11th Grade

Medium

CCSS
HSF-IF.C.7B, HSF-IF.C.7D, 8.F.B.4

+1

Standards-aligned

Created by

Kerri Furbush

Used 16+ times

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Name the locations of all JUMP discontinuities.

-4, -1

-4, 0, 1

0

-4, 0

Tags

CCSS.HSF-IF.C.7D

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Name the locations of all REMOVABLE discontinuities.

-1, 2, 4

-1, 1, 4

1, 4

-1, 4

Tags

CCSS.HSF-IF.C.7D

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Name the locations of all INFINITE discontinuities.

-4

-4, 0

0

Tags

CCSS.HSF-IF.C.7D

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Name the types and locations of all discontinuities.

Removable at x = -1, Jump at x = 2

Infinite at x = -1, Jump at x = 2

Removable at x = -1, Infinite at x = 2

Jump at x = -1, Infinite at x = 2

Tags

CCSS.HSF-IF.C.7B

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

At what values should you evaluate to determine if the function is continuous?

1 and 2

1 and 3

-1 and 5

-1 and 3

Tags

CCSS.HSF-IF.C.7B

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Is the following function is continuous at x=0?

Continuous

Discontinuous

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Is the following function continuous at

 x=1x=1  ?

Yes, because  2(1) 1 = 12\left(1\right)\ -1\ =\ 1  and  (1)2 =1\left(1\right)^2\ =1  

No, because  2(1) 1 =12\left(1\right)\ -1\ =1  and  (1)2=2\left(1\right)^2=2  

No, because  (1)2=1\left(1\right)^2=1  and  (1)2+(1)30(1)5=7\frac{\left(1\right)^2+\left(1\right)-30}{\left(1\right)-5}=7  

Tags

CCSS.HSF-IF.C.7B

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Is the following function continuous at  x=3x=3  

Yes, because  2(1) 1 = 12\left(1\right)\ -1\ =\ 1  and  (1)2 =1\left(1\right)^2\ =1  

No, because  2(3) 1 =52\left(3\right)\ -1\ =5  and  (3)2=9\left(3\right)^2=9  

No, because  (3)2=9\left(3\right)^2=9  and  (3)2+(3)30(3)5=7\frac{\left(3\right)^2+\left(3\right)-30}{\left(3\right)-5}=7  

Tags

CCSS.HSF-IF.C.7B