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Progress check 8.2 (11 -->18)

Authored by Peter Hoferle

Chemistry

11th - 12th Grade

NGSS covered

Used 12+ times

Progress check 8.2 (11 -->18)
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9 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The weak acid  CH3COOHCH_3COOH   has a pKa of 4.76. A solution is prepared by mixing 500.mL of 0.150M  CH_3COOH  and 0.0200mol of NaOH(s). Which of the following can be used to calculate the pH of the solution?

pH=4.76 + log (0.02000.150)=3.88\left(\frac{0.0200}{0.150}\right)=3.88  

pH = 4.76 + log (0.02000.0750)=4.19\left(\frac{0.0200}{0.0750}\right)=4.19  

pH = 4.76 + log (0.02000.0550)=4.32\left(\frac{0.0200}{0.0550}\right)=4.32  

pH = 4.76 + log (0.09500.0750)=4.86\left(\frac{0.0950}{0.0750}\right)=4.86  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the following provides the correct mathematical expression to calculate the pH of a solution made by mixing 10.0ml of 1.00MHCl and 11.0mL of 1.00MNaOH at 25oC?

pH=−log(0.0010)=3.00pH=−log(0.0010)=3.00

pH=14.00+log(0.001)=11.00

pH = 14.00 + log (0.00100.0210)=12.68\left(\frac{0.0010}{0.0210}\right)=12.68

pH = 14.00 + log (0.00100.0110)=12.96\left(\frac{0.0010}{0.0110}\right)=12.96

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

A buffer solution is formed by mixing equal volumes of 0.12 M NH3(aq) and 0.10 M HCl(aq), which reduces the concentration of both solutions by one half. Based on the pKa data given in the table, which of the following gives the pH of the buffer solution?

pH=−log(0.050)=1.30

pH = 9.25 + log (0.0100.050)=8.55\left(\frac{0.010}{0.050}\right)=8.55

pH = 9.25 + log (0.0600.050)=9.32\left(\frac{0.060}{0.050}\right)=9.32

pH = 14.00 -(-log(0.010)) = 12.00

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

The pH versus volume data for the titration of 0.10 M HNO2(aq) with 0.10 M KOH(aq) is plotted on the graph above. Based on the data, which of the following species is present in the greatest concentration after 6.0mL of KOH(aq) has been added to the solution of HNO2(aq) ?

H+(aq)

HNO2(aq)

NO2-(aq)

OH(aq)

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

A 0.20M solution of the weak acid potassium hydrogen phthalate (KHP) is titrated with 0.10MNaOH(aq). Based on the titration curve shown in the graph above, the pKa of KHP is closest to which of the following?


Answer D

3.6

5.4

8.8

11.8

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

A 60.mL sample of NaOH(aq) was titrated with 0.10MHCl(aq). Based on the resulting titration curve shown above, what was the approximate concentration of NaOH in the sample?

0.033M

0.050M

0.10M

0.20M

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

The table above provides information on two weak acids. Which of the following explains the difference in their acid strength?

Acid 1 is a stronger acid because it has more acidic hydrogen atoms than acid 2.

Acid 1 is a stronger acid because it can make more hydrogen bonds than acid 2.

Acid 2 is a stronger acid because it is a larger, more polarizable molecule with stronger intermolecular forces than acid 1.

Acid 2 is a stronger acid because it has a more stable conjugate base than acid 1 due to the greater number of electronegative Br atoms.

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