P o l e p r o s t o k ą t a o d ł u g o s ˊ c i 3 2 i s z e r o k o s ˊ c i 2 6 j e s t r o ˊ w n e : Pole\ prostokąta\ o\ \ długości\ 3\sqrt{2\ }\ i\ szerokości\ 2\sqrt{6}jest\ równe: P o l e p r o s t o k ą t a o d ł u g o s ˊ c i 3 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> i s z e r o k o s ˊ c i 2 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> j e s t r o ˊ w n e :

12 3 12\sqrt{3} 1 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 8 6\sqrt{8} 6 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 12 5\sqrt{12} 5 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Potęgi i pierwiastki - sprawdzian

Authored by Joanna Strojny-Gargula

Mathematics

7th Grade

Used 95+ times

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15 questions

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MULTIPLE SELECT QUESTION

2 mins • 1 pt

Wyrażenie (−2)·(−2)·(−2)·(−2)·(−2)·(−2) można zapisać w postaci:

−2⁶

6²

(−2)⁶

- 64

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Wartość wyrażenia wynosi: $\frac{3^{11\ }:\ \left(3^6\cdot3^2\right)}{3^2}$

$\frac{1}{3}$

$3^5$

MULTIPLE SELECT QUESTION

2 mins • 1 pt

$\sqrt{32+25}=\sqrt{32}+\sqrt{25}=4\sqrt{2}+5$

prawda

fałsz

MULTIPLE SELECT QUESTION

2 mins • 1 pt

0,00011 zapisane w notacji wykładniczej to 1,1⋅10^-5

prawda

fałsz

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Ola uważa, że −3⁴ oraz (−3)⁴ dają wynik dodatni. Ala uważa, że to nieprawda. Kto ma rację?

Ola

Ala

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

- 10

- 9

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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Potęgi i pierwiastki - sprawdzian

Wyrażenie (−2)·(−2)·(−2)·(−2)·(−2)·(−2) można zapisać w postaci:

Wartość wyrażenia wynosi: 311 : (36⋅32)32\frac{3^{11\ }:\ \left(3^6\cdot3^2\right)}{3^2}32311 : (36⋅32)​

32+25=32+25=42+5\sqrt{32+25}=\sqrt{32}+\sqrt{25}=4\sqrt{2}+532+25​=32​+25​=42​+5

0,00011 zapisane w notacji wykładniczej to 1,1⋅10-5

Ola uważa, że −34 oraz (−3)4 dają wynik dodatni. Ala uważa, że to nieprawda. Kto ma rację?

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Wartość wyrażenia wynosi: $\frac{3^{11\ }:\ \left(3^6\cdot3^2\right)}{3^2}$

$\sqrt{32+25}=\sqrt{32}+\sqrt{25}=4\sqrt{2}+5$

0,00011 zapisane w notacji wykładniczej to 1,1⋅10^-5

Ola uważa, że −3⁴ oraz (−3)⁴ dają wynik dodatni. Ala uważa, że to nieprawda. Kto ma rację?