Molecular Orbital Theory

Atoms that are sp2 hybridized form ____ pi bond(s).

• 0

• 1

• 2

• 3

Which of the following statements is true?

• Electrons are never found in an antibonding MO.

• All antibonding MOs are higher in energy than the atomic orbitals of which they are composed.

• Antibonding MOs have electron density mainly outside the space between the two nuclei.

• Two of the statements are true.

The electron configuration of a particular diatomic species is (σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)⁴. What is the bond order for this species?

• 1.5

• 1

• 0.5

• 0

Tags

NGSS.HS-PS1-4

What is the bond order of He₂⁺?

• 2

• 0

• 1/2

• 1

Tags

NGSS.HS-PS1-2

If four orbitals on one atom overlap four orbitals on a second atom, how many molecular orbitals will form?

• 1

• 4

• 8

• 16

• None of the answers are correct

When comparing Be₂ and H₂:

I.Be₂ is more stable because it contains both bonding and antibonding valence electrons.

II.H₂ has a higher bond order than Be₂.

III.H₂ is more stable because it only contains σ1s electrons.

IV.H₂ is more stable because it is diamagnetic, whereas Be₂ is paramagnetic.

• I, II

• III, IV

• II, III

• II, IV

Tags

NGSS.HS-PS1-2

If a molecule demonstrates paramagnetism, then :

I.The substance can have both paired and unpaired electrons.

II.The bond order is not a whole number.

III.It can be determined by drawing a Lewis structure.

IV.It must be an ion.

• I, II

• II,III

• I, II, IV

• I only

Tags

NGSS.HS-PS1-1

For which of the following diatomic molecules would the bond order become greater if an electron is removed (i.e., if the molecule is converted to the positive ion in its ground state)?

• B₂

• C₂

• H₂

• F₂

Tags

NGSS.HS-PS1-4

How many of the following: F₂, B₂, O₂, N₂ , are paramagnetic?

• 4

• 1

• 2

• 3

Tags

NGSS.HS-PS1-2

NGSS.HS-PS1-1

What are the essential conditions to form a molecule from combination of AOs?

• Energy of AOs should be similar

• Overlap between AOs should be maximum

• Combining AOs should have similar symmetry

• All of the above