Thermochemistry Summative Assessment

Thermochemistry Summative Assessment

10th - 12th Grade

8 Qs

quiz-placeholder

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Thermochemistry Summative Assessment

Thermochemistry Summative Assessment

Assessment

Quiz

Chemistry

10th - 12th Grade

Easy

NGSS
HS-PS1-4, HS-PS3-1, HS-PS3-4

Standards-aligned

Created by

Allyson Watson

Used 10+ times

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Exothermic means a

reaction does what?

Releases energy

Absorbs energy

Translates energy

Has specific

capacity

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Heat is measured in 
joules
grams
degrees celcius

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The specific heat(c) of copper is 0.39 J/g °C. What is the temperature change(∆t) when 100 Joules of heat(Q) is added to 20 grams?
12.82 °C
24.12°C
351 °C

Tags

NGSS.HS-PS3-1

NGSS.HS-PS3-4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

H2 + 2 C + N+ 270.3 kJ --> 2 HCN
Is this reaction endothermic or exothermic?
Endothermic 
Exothermic

Tags

NGSS.HS-PS1-4

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A 24.0 gram sample of copper was heated from 25.0oC to 500.0oC, 4378J of heat were absorbed, what is the specific heat of copper?
.384
49909200
2.60
8.77

Tags

NGSS.HS-PS3-1

NGSS.HS-PS3-4

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If ΔH is positive, heat would be shown on the _____ side of the thermochemical equation.
Reactant
Product

Tags

NGSS.HS-PS1-4

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The enthalpy change for the reaction
C(s, graphite) + 1⁄2O
2(g) --> CO(g)
cannot be measured directly since some carbon dioxide is always formed in the reaction.
It can be calculated using Hess’s Law and the enthalpy changes of combustion of graphite and of carbon monoxide.
C(s, graphite) + O2(g) --> CO2    ΔH=-394 kJmol–1
CO(g) + 1⁄2O2(g) --> CO2  
ΔH=-283 kJmol–1  
The enthalpy change for the reaction of graphite with oxygen to give carbon monoxide is 
-677 kJmol–1 
+111 kJmol–1 
-111 kJmol–1 
+677 kJmol–1 

Tags

NGSS.HS-PS1-4

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The enthalpies of combustion of C(s), H2(g) and C4H9OH(l) (in kJmol-1) are as follows  
C(s) + O
2(g)   ->  CO2(g)  
                                             ∆H=a
H2(g) + ½O2(g)   ->   H2O(l)                                        ∆H=b
C4H9OH(l) + 6O2(g)   ->   4CO2(g) + 5H2O(l)  ∆H=c
What is the enthalpy change for the reaction shown below?
  4C(g) + 5H2(l) + ½O2(g)   ->   C4H9OH(l)
c – 4a – 5b
2a + 10b - c
4a + 5b - c
2a + 5b + c

Tags

NGSS.HS-PS1-4