7.5 Angle Bisector Theorem

According to the Triangle Angle Bisector Theorem, which proportion is set up correctly?

• $\frac{6}{x}=\frac{9}{15}$

• $\frac{9}{6}=\frac{15}{x}$

• $\frac{x}{6}=\frac{15}{9}$

• All of the above
  

Tags

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Find the missing length if the proportion is  $\frac{12}{x}=\frac{20}{25}$  

• 25

• 15

• 6

• 16

Tags

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Find the missing length.

• 25

• 20

• 21

• 15

Tags

CCSS.7.G.A.1

Solve for x.

• 7

• 6

• 10

• 3

Tags

CCSS.7.EE.B.4

CCSS.7.G.B.5

Solve for x if the proportion for solving it is.
 $\frac{9}{6}=\frac{x+7}{8}$  

• 5

• 10

• 3

• 8

Tags

CCSS.7.EE.B.3

CCSS.7.EE.B.4

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Solve for x if the proportion for solving it is
 $\frac{9}{24}=\frac{15}{5x+10}$  

• 10

• 9

• 6

• 5

Tags

CCSS.7.EE.B.3

CCSS.7.EE.B.4

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Solve for x.

• 8

• 4

• 7

• 5

Tags

CCSS.7.EE.A.1

CCSS.7.EE.B.3

CCSS.7.EE.B.4

Solve for x.

• 8

• 7

• 5

• 10

Tags

CCSS.7.EE.A.1

CCSS.7.EE.B.3

CCSS.7.EE.B.4

Which is the correct proportion for solving for x?

• $\frac{5x+5}{35}=\frac{16}{44}$

• $\frac{5x+5}{35}=\frac{16}{28}$

• $\frac{16}{44}=\frac{5x+5}{35}$

• no solution
  

Tags

CCSS.7.EE.B.3

CCSS.7.EE.B.4

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Solve for x.

• 3

• 10

• 9

• 7

Tags

CCSS.7.EE.B.3

CCSS.7.EE.B.4

CCSS.7.G.B.5