12-5 Circles in the Coordinate Plane

Write the equation of a circle with center (7, 0) with radius 3.

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

Tags

CCSS.HSG.GPE.A.1

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units
• Center (4,3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=4
• x²+y²=81
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)
• (0, 0)
• not enough information

Tags

CCSS.HSG.GPE.A.1

In the equation
(x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

The point (-3, 4) is on a circle with center (1, -1). Write the standard equation of the circle.

• (x + 1)² + (y - 1)² = 41

• (x - 1)² + (y + 1)² = 16

• (x + 1)² + (y - 1)² = 1681

• (x - 1)² + (y + 1)² = 41

Tags

CCSS.HSG.GPE.A.1

The point (-3, 4) is on a circle with center (1, -1). Write the standard equation of the circle.

• (x + 1)² + (y - 1)² = 41

• (x - 1)² + (y + 1)² = 16

• (x + 1)² + (y - 1)² = 1681

• (x - 1)² + (y + 1)² = 41