QUEST:Alg2Trig, 6.17-19

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

Use the change of base rule to rewrite this problem:

log₃64

• $\frac{\log64}{\log\ 3}$
  

• $\frac{\log\ 3}{\log\ 64}$

• $\log\ \frac{64}{3}$

• $\log\ \frac{3}{64}$

Solve

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

Solve for x.
 $\log_3\left(2x-6\right)=\log_3\left(3x-7\right)$  

• -3

• 14

• -8

• No solution

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve for x.
 $\log_3\left(7\right)+\log_3\left(2x\right)=2$  

•  $-\frac{9}{8}$  

•  $\frac{13}{2}$  

•  $\frac{9}{14}$  

•  $\frac{9}{40}$  

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

 $\log\ \left(9-x\right)=\log\ \left(2x-6\right)$ 

 Solve for x

• 5

• -11

•  $\frac{18}{19}$  

• -4

 $\log_3\left(n^2+4n\right)=\log_3\left(35+2n\right)$  

Solve for n

• 5

• 5, -7

• -3, 5

• -7

Solve for x given:

-10log₂ x + 8 = -12

• 8

• 12

• 1296

• 4

 $\log_4\ 7\ +\ \log_{4\ }\left(x\ -\ 2\right)\ =\ \log_4\ 62$  

Solve for x

•  $\frac{76}{7}$  

•  $-\frac{19}{6}$  

• 42

•  $\frac{10}{3}$  

 $10^{3x}=4$  

Solve for x

• -0.20

• 0.60

• 0.20

• -0.60