Si A → = ( − 2 ; 3 ) \overrightarrow{A}=\left(-2;3\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 2 ; 3 ) y B → = ( 5 ; 8 ) \overrightarrow{B}=\left(5;8\right) B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 5 ; 8 ) entonces R → = A → + B → \overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B} R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> es:

( 3 ; 11 ) \left(3;11\right) ( 3 ; 1 1 )

( − 3 ; 11 ) \left(-3;11\right) ( − 3 ; 1 1 )

( 3 ; 5 ) \left(3;5\right) ( 3 ; 5 )

SUMA DE VECTORES 9° Quiz

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

La suma de vectores da como respuesta un:

VECTOR

MÓDULO

ÁNGULO

GRÁFICO

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Si $\overrightarrow{A}=\left(-2;3\right)$ y $\overrightarrow{B}=\left(5;8\right)$ entonces $\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$ es:

$\left(3;11\right)$

$\left(-3;11\right)$

$\left(3;5\right)$

$14$

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle:

$\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

(9;0)

9

-9

(0;9)

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle el módulo de: $\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

(9;0)

9

-9

(0;9)

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle el módulo de:

$\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

1

-1

7

(-1;0)

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

(0;6)

(6;0)

(0;0)

6

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

(0;6)

(6;0)

(0;0)

0

8.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

9.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

(-3;-4)

(3;-4)

(3;4)

(-4;-3)

10.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Del gráfico halle el módulo de: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

5

-5

7

-7

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SUMA DE VECTORES 9°

La suma de vectores da como respuesta un:

Si A→=(−2;3)\overrightarrow{A}=\left(-2;3\right)A=(−2;3) y B→=(5;8)\overrightarrow{B}=\left(5;8\right)B=(5;8) entonces R→=A→+B→\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}R=A+B es:

Del gráfico halle: R→=A→+B→\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}R=A+B

Del gráfico halle el módulo de: R→=A→+B→\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}R=A+B

Del gráfico halle el módulo de: R→=A→+B→\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}R=A+B

Del gráfico halle: R→=P→+Q→\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}R=P+Q​

Del gráfico halle: R→=P→+Q→\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}R=P+Q​

Del gráfico halle: R→=P→+Q→\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}R=P+Q​

Del gráfico halle: R→=P→+Q→\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}R=P+Q​

Del gráfico halle el módulo de: R→=P→+Q→\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}R=P+Q​

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Discover more resources for Physics

Si $\overrightarrow{A}=\left(-2;3\right)$ y $\overrightarrow{B}=\left(5;8\right)$ entonces $\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$ es:

Del gráfico halle:

$\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

Del gráfico halle el módulo de: $\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

Del gráfico halle el módulo de:

$\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

Del gráfico halle: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$

Del gráfico halle el módulo de: $\overrightarrow{R}=\overrightarrow{P}+\overrightarrow{Q}$