f ( x ) = x f\left(x\right)=\sqrt{x} f ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> och g ( x ) = x + 3 g\left(x\right)=x+3 g ( x ) = x + 3 h ( x ) = x ( x + 3 ) h\left(x\right)=\sqrt{x}\left(x+3\right) h ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( x + 3 )

h ( x ) = f ( x ) ⋅ g ( x ) h\left(x\right)=f\left(x\right)\cdot g\left(x\right) h ( x ) = f ( x ) ⋅ g ( x )

h ( x ) = f ( g ( x ) ) h\left(x\right)=f\left(g\left(x\right)\right) h ( x ) = f ( g ( x ) )

h ( x ) = g ( f ( x ) ) h\left(x\right)=g\left(f\left(x\right)\right) h ( x ) = g ( f ( x ) )

h ( x ) h\left(x\right) h ( x ) är inget av det

f ( x ) = x f\left(x\right)=\sqrt{x} f ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> och g ( x ) = x + 3 g\left(x\right)=x+3 g ( x ) = x + 3 h ( x ) = x + 3 h\left(x\right)=\sqrt{x+3} h ( x ) = x + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

h ( x ) = f ( g ( x ) ) h\left(x\right)=f\left(g\left(x\right)\right) h ( x ) = f ( g ( x ) )

h ( x ) = g ( f ( x ) ) h\left(x\right)=g\left(f\left(x\right)\right) h ( x ) = g ( f ( x ) )

h ( x ) = f ( x ) ⋅ g ( x ) h\left(x\right)=f\left(x\right)\cdot g\left(x\right) h ( x ) = f ( x ) ⋅ g ( x )

h ( x ) h\left(x\right) h ( x ) är inget av det

f ( x ) = x f\left(x\right)=\sqrt{x} f ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> och g ( x ) = x + 3 g\left(x\right)=x+3 g ( x ) = x + 3 h ( x ) = x + x + 3 h\left(x\right)=\sqrt{x}+x+3 h ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + x + 3

h ( x ) h\left(x\right) h ( x ) är inget av det

h ( x ) = f ( g ( x ) ) h\left(x\right)=f\left(g\left(x\right)\right) h ( x ) = f ( g ( x ) )

h ( x ) = g ( f ( x ) ) h\left(x\right)=g\left(f\left(x\right)\right) h ( x ) = g ( f ( x ) )

h ( x ) = f ( x ) ⋅ g ( x ) h\left(x\right)=f\left(x\right)\cdot g\left(x\right) h ( x ) = f ( x ) ⋅ g ( x )

Bredvid eller inuti? förkunskap till kedje- och produktregel

Authored by Svetlana Yushmanova

Mathematics

12th Grade

Used 6+ times

Bredvid eller inuti? förkunskap till kedje- och produktregel

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9 questions

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(x\right)+g\left(x\right)$

$h\left(x\right)=e^{2x}+e^x$

$h\left(x\right)=e^{x^2+x}$

$h\left(x\right)=\left(x^2+x\right)\cdot e^x$

$h\left(x\right)=x^2+x+e^x$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

$h\left(x\right)=e^{2x}+e^x$

$h\left(x\right)=e^{x^2+x}$

$h\left(x\right)=\left(x^2+x\right)\cdot e^x$

$h\left(x\right)=x^2+x+e^x$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=e^{2x}+e^x$

$h\left(x\right)=e^{x^2+x}$

$h\left(x\right)=\left(x^2+x\right)\cdot e^x$

$h\left(x\right)=x^2+x+e^x$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=e^{2x}+e^x$

$h\left(x\right)=e^{x^2+x}$

$h\left(x\right)=\left(x^2+x\right)\cdot e^x$

$h\left(x\right)=x^2+x+e^x$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2$ och $g\left(x\right)=x+3$

$h\left(x\right)=\left(x+3\right)^2$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

Answer explanation

Först lägger jag till 3, sedan kvadrerar, därför sitter g(x) inuti f(x),
därmed är svaret $f\left(g\left(x\right)\right)$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=x^2$ och $g\left(x\right)=x+3$

$h\left(x\right)=x^2\left(x+3\right)$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

Answer explanation

De sitter bredvid varandra:
man kvadrerar x-et, lägger till 3 till ett annat x och sedan multiplicerar ihop
finns ingen given ordning i vilken man ska göra saker

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x}\left(x+3\right)$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

$h\left(x\right)$ är inget av det

Answer explanation

De sitter bredvid varandra: man drar roten ur x-et, lägger till 3 till ett annat x och sedan multiplicerar ihop

finns ingen given ordning i vilken man ska göra saker

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x+3}$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

$h\left(x\right)$ är inget av det

Answer explanation

Först lägger man till tre , sedan drar man roten ur, därför sitter g(x) inuti f(x),därmed är svaret $f\left(g\left(x\right)\right)$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x}+x+3$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

$h\left(x\right)$ är inget av det

Answer explanation

h(x) är summan av f(x) och g(x)

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Bredvid eller inuti? förkunskap till kedje- och produktregel

f(x)=x2+xf\left(x\right)=x^2+xf(x)=x2+x och g(x)=exg\left(x\right)=e^xg(x)=ex h(x)=f(x)+g(x)h\left(x\right)=f\left(x\right)+g\left(x\right)h(x)=f(x)+g(x)

f(x)=x2+xf\left(x\right)=x^2+xf(x)=x2+x och g(x)=exg\left(x\right)=e^xg(x)=ex h(x)=f(x)⋅g(x)h\left(x\right)=f\left(x\right)\cdot g\left(x\right)h(x)=f(x)⋅g(x)

f(x)=x2+xf\left(x\right)=x^2+xf(x)=x2+x och g(x)=exg\left(x\right)=e^xg(x)=ex h(x)=g(f(x))h\left(x\right)=g\left(f\left(x\right)\right)h(x)=g(f(x))

f(x)=x2+xf\left(x\right)=x^2+xf(x)=x2+x och g(x)=exg\left(x\right)=e^xg(x)=ex h(x)=f(g(x))h\left(x\right)=f\left(g\left(x\right)\right)h(x)=f(g(x))

f(x)=x2f\left(x\right)=x^2f(x)=x2 och g(x)=x+3g\left(x\right)=x+3g(x)=x+3 h(x)=(x+3)2h\left(x\right)=\left(x+3\right)^2h(x)=(x+3)2

Först lägger jag till 3, sedan kvadrerar, därför sitter g(x) inuti f(x),därmed är svaret f(g(x))f\left(g\left(x\right)\right)f(g(x))

f(x)=x2f\left(x\right)=x^2f(x)=x2 och g(x)=x+3g\left(x\right)=x+3g(x)=x+3 h(x)=x2(x+3)h\left(x\right)=x^2\left(x+3\right)h(x)=x2(x+3)

De sitter bredvid varandra:man kvadrerar x-et, lägger till 3 till ett annat x och sedan multiplicerar ihopfinns ingen given ordning i vilken man ska göra saker

f(x)=xf\left(x\right)=\sqrt{x}f(x)=x​ och g(x)=x+3g\left(x\right)=x+3g(x)=x+3 h(x)=x(x+3)h\left(x\right)=\sqrt{x}\left(x+3\right)h(x)=x​(x+3)

De sitter bredvid varandra: man drar roten ur x-et, lägger till 3 till ett annat x och sedan multiplicerar ihopfinns ingen given ordning i vilken man ska göra saker

f(x)=xf\left(x\right)=\sqrt{x}f(x)=x​ och g(x)=x+3g\left(x\right)=x+3g(x)=x+3 h(x)=x+3h\left(x\right)=\sqrt{x+3}h(x)=x+3​

Först lägger man till tre , sedan drar man roten ur, därför sitter g(x) inuti f(x),därmed är svaret f(g(x))f\left(g\left(x\right)\right)f(g(x))

f(x)=xf\left(x\right)=\sqrt{x}f(x)=x​ och g(x)=x+3g\left(x\right)=x+3g(x)=x+3 h(x)=x+x+3h\left(x\right)=\sqrt{x}+x+3h(x)=x​+x+3

h(x) är summan av f(x) och g(x)

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$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(x\right)+g\left(x\right)$

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(x\right)\cdot g\left(x\right)$

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=g\left(f\left(x\right)\right)$

$f\left(x\right)=x^2+x$ och $g\left(x\right)=e^x$

$h\left(x\right)=f\left(g\left(x\right)\right)$

$f\left(x\right)=x^2$ och $g\left(x\right)=x+3$

$h\left(x\right)=\left(x+3\right)^2$

Först lägger jag till 3, sedan kvadrerar, därför sitter g(x) inuti f(x),
därmed är svaret $f\left(g\left(x\right)\right)$

$f\left(x\right)=x^2$ och $g\left(x\right)=x+3$

$h\left(x\right)=x^2\left(x+3\right)$

De sitter bredvid varandra:
man kvadrerar x-et, lägger till 3 till ett annat x och sedan multiplicerar ihop
finns ingen given ordning i vilken man ska göra saker

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x}\left(x+3\right)$

De sitter bredvid varandra: man drar roten ur x-et, lägger till 3 till ett annat x och sedan multiplicerar ihop

finns ingen given ordning i vilken man ska göra saker

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x+3}$

Först lägger man till tre , sedan drar man roten ur, därför sitter g(x) inuti f(x),därmed är svaret $f\left(g\left(x\right)\right)$

$f\left(x\right)=\sqrt{x}$ och $g\left(x\right)=x+3$

$h\left(x\right)=\sqrt{x}+x+3$