Systems of equations Alg 1 final exam

What is the solution to the system of equations? 
y = 3x - 8
y = 4 - x

• (3,1)
• (1,3)
• (-3,1)
• (3,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by elimination. 
−4x − 4y = 0
4x + 4y = 0 

• (−6, −4) 
• Infinite number of solutions  
• (−6, 10) 
• (6, 4) 

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using elimination.
3x + 2y = 16
7x + y = 19

• (-2,5)
• (-2,-5)
• (2,-5)
• (2,5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations:

• (0,3)
• (0,3)
• (3,0)
• (0,-3)

Tags

CCSS.HSA.REI.C.9

Solve the system of equations.
-8x + 7y = 9
x = -2

• (-2, -1)
• (-2, 3)
• (-1, -2)
• (-2, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations.
x + 3y = -17
2x + 3y = -7

• (1, -20)
• (3, 0)
• (-5, -2)
• (10 , -9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which of the following are ways to solve systems of equations? 

• Graphing
• Substitution
• Elimination
• All of the above

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution.

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step in solving a system of equations by elimination?

• Get both equations in standard form and line up the like terms.

• Get both equations in slope-intercept form.

• Get both equations equal to zero.

• Put the x terms first.