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ULANGAN SEMESTER II

Authored by ishak ishak

Chemistry

11th Grade

Used 1+ times

ULANGAN SEMESTER II
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35 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bilangan kuantum azimut dari semua orbital yang terdapat pada kulit L(n=2) adalah....

n = 2 -> l = 0 dan 1

n = 3 -> l = 1 dan 2

n = 4 -> l = 2 dan 3

n = 2 -> l = 2 dan 3

n = 3 -> l = 0 dan 1

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Keempat bilangan kuantum pada elektron terluar pada kulit terluar ₁₅X adalah ....

s = - ½; n = 4; l = 0; m = 0

s = + ½; n = 3; l = 1; m =+1

s = - ½; n = 2; l = 1; m = 0

s = + ½; n = 3; l = 2; m = 0

s = + ½; n = 2; l = 2; m = 3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Harga keempat bilangan kuantum elektron pada kulit terluar unsur 20X adalah....

s = + ½; l = 0 ; n = 4 ; m = 3

s = - ½; l = 0 ; n = 4 ; m = 4

s = + ½; l = 0 ; n = 4 ; m = 0

s = - ½; l = 0 ; n = 4 ; m = 0

s = - ½; l = 2 ; n = 4 ; m = 5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Unsur X bernomor atom 8, maka harga keempat bilangan kuantum elektron terakhir unsur tersebut adalah ….

n = 2; l = 0; m = 0; s = – ½

n = 2; l = 1; m = -1; s = + ½

n = 2; l = 1; m = 1; s = + ½

n = 2; l = 1; m = -1; s = – ½

n = 2; l = 1; m = 0; s = – ½

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Elektron dengan bilangan kuantum n = 3, l = 2, m = 0, s = ½ terletak pada….

n = 4 kulit M, l = 2 subkulit d, m = 1 orbital d

n = 3 kulit M, l = 2 subkulit d, m = 0 orbital s

n = 3 kulit M, l = 2 subkulit d, m = 0 orbital p

n = 2 kulit M, l = 2 subkulit d, m = 3 orbital d

n = 3 kulit M, l = 2 subkulit d, m = 4 orbital f

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tentukan keempat bilangan kuantum dari unsur 27X !

n = 4; l = 1; m = 2; s = - ½

n = 4; l = 0; m = 0; s = - ½

n = 4; l = 1; m = 2; s = - ½

n = 4; l = 1; m = 0; s = - ½

n = 4; l = 0; m = 2; s = - ½

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

4 bilangan kuantum dari electron terakhir untuk atom X dengan nomor atom 38 adalah....

n = 5; l = 2; m= 1; s = - ½

n = 2; l = 0; m= 0; s = - ½

n = 4; l = 2; m= 1; s = - ½

n = 2; l = 0; m= 0; s = - ½

n = 5; l = 0; m =0; s = - ½

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