Solving Proportional Relationships With Equations A

Solving Proportional Relationships With Equations A

7th Grade

10 Qs

quiz-placeholder

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Solving Proportional Relationships With Equations A

Solving Proportional Relationships With Equations A

Assessment

Quiz

Mathematics

7th Grade

Medium

CCSS
4.NF.A.1, 5.NF.B.5B, 7.RP.A.3

+2

Standards-aligned

Created by

Melissa Hogg

Used 1+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Are they equivalent? Check using cross products. Which equation correctly shows your work?
 36=24\frac{3}{6}=\frac{2}{4}  

3 x 4 = 6 x 2

3  x 2 = 6 x 4

3 + 4 = 6 + 2

3  + 2 = 6 + 4

Tags

CCSS.3.NF.A.3A

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What number do you get when you multiply the cross products? 
\frac{3}{6}=\frac{2}{4}  

6

5

12

10

Tags

CCSS.5.NF.B.5B

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 26 = 515\frac{2}{6}\ =\ \frac{5}{15}  

Determine if the following are equivalent using cross products. Which equation would show the correct work? 

2 x 5 = 6 x 15

2 x 15 = 6 x 5 

15-5 = 6-2

2 + 15 = 6 + 5

Tags

CCSS.3.NF.A.3A

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 26 =515\frac{2}{6}\ =\frac{5}{15}  

What number do you get when you multiply the cross products?

17

11

20

30

Tags

CCSS.4.NF.A.1

CCSS.5.NF.B.5B

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 927 =y12\frac{9}{27}\ =\frac{y}{12}  

Solve for y using cross multiplication. Which of the following would represent step 1 of the work needed to solve? 

27 +  y = 9 + 12

 27y=91227\cdot y=9\cdot12  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 927 =y12\frac{9}{27}\ =\frac{y}{12}  

Solve for y using cross multiplication. Which of the following would represent step 2 of the work needed to solve? 

27y = 20

 27y=10827y=108  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 927 =y12\frac{9}{27}\ =\frac{y}{12}  

Solve for y using cross multiplication. 

y = 4

 y=3y=3  

Tags

CCSS.7.RP.A.3

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