Law of Sines

Law of Sines

11th - 12th Grade

18 Qs

quiz-placeholder

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Law of Sines

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Assessment

Quiz

Mathematics

11th - 12th Grade

Hard

CCSS
HSG.SRT.D.11, HSG.SRT.D.10, HSG.SRT.C.6

+1

Standards-aligned

Created by

Alison Fauerbach

Used 82+ times

FREE Resource

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Identify the Law of Sines

sin2x+cos2x=1\sin^2x+\cos^2x=1

sin(A)a=sin(B)b=sin(C)c\frac{\sin\left(A\right)}{a}=\frac{\sin\left(B\right)}{b}=\frac{\sin\left(C\right)}{c}

sin(A)sin(B)sin(C)=1\sin\left(A\right)\sin\left(B\right)\sin\left(C\right)=1

Soh Cah Toa

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Which of the following scenarios would you be unable to use Law of Sines?

AAS

ASA

SSA

SSS

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

For which scenario would you need to use the ambiguous case?

SSS

AAS

ASA

SSA

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which equation shows how you would use the law of sines to find angle A?

 sin4426=sin A23\frac{\sin44}{26}=\frac{\sin\ A}{23} 

 sin 2644=sin 23A\frac{\sin\ 26}{44}=\frac{\sin\ 23}{A} 

 sin 4423=sin A26\frac{\sin\ 44}{23}=\frac{\sin\ A}{26} 

 sin2344=sin 26A\frac{\sin23}{44}=\frac{\sin\ 26}{A} 

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which equation shows how you would use the law of sines to find angle B?

sin7941=sin B35\frac{\sin79}{41}=\frac{\sin\ B}{35}

sin 4179=sin 35B\frac{\sin\ 41}{79}=\frac{\sin\ 35}{B}

sin 7935=sin B41\frac{\sin\ 79}{35}=\frac{\sin\ B}{41}

sin3579=sin 41B\frac{\sin35}{79}=\frac{\sin\ 41}{B}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which equation shows how you would use the law of sines to find side c?

 sin4119=sin 75c\frac{\sin41}{19}=\frac{\sin\ 75}{c} 

 sin 6419=sin 75c\frac{\sin\ 64}{19}=\frac{\sin\ 75}{c} 

 sin 1964=sin c75\frac{\sin\ 19}{64}=\frac{\sin\ c}{75} 

 sin1941=sin c75\frac{\sin19}{41}=\frac{\sin\ c}{75} 

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find AC to the nearest tenth.

33.4

35

31.9

30

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

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