BILANGAN BERPANGKAT POSITIF & NEGATIF

BILANGAN BERPANGKAT POSITIF & NEGATIF

8th Grade

25 Qs

quiz-placeholder

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BILANGAN BERPANGKAT POSITIF & NEGATIF

BILANGAN BERPANGKAT POSITIF & NEGATIF

Assessment

Quiz

Mathematics

8th Grade

Practice Problem

Medium

CCSS
6.EE.A.1, 6.EE.A.2, 6.EE.A.3

+1

Standards-aligned

Created by

Fitri Solihah

Used 118+ times

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25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 Pernyataan yang tidak benar adalah ...Pernyataan\ yang\ tidak\ benar\ adalah\ ... 

 25=2×2×2×2×22^5=2\times2\times2\times2\times2  

 (3)4=(3)×(3)×(3)×(3)\left(-3\right)^4=\left(-3\right)\times\left(-3\right)\times\left(-3\right)\times\left(-3\right)  

 (2)4=(2)×(2)×(2)×(2)-\left(2\right)^4=\left(-2\right)\times\left(-2\right)\times\left(-2\right)\times\left(-2\right)  

 (15)4=(15)×(15)×(15)×(15)-\left(\frac{1}{5}\right)^4=-\left(\frac{1}{5}\right)\times\left(\frac{1}{5}\right)\times\left(\frac{1}{5}\right)\times\left(\frac{1}{5}\right)  

2.

MULTIPLE SELECT QUESTION

15 mins • 1 pt

Pernyataan yang benar adalah .... (jawaban bisa lebih dari satu)

 (2)3=8\left(-2\right)^3=-8  

 (3)4=81\left(-3\right)^4=81  

 (5)4=625-\left(5\right)^4=625  

 (12)3=18\left(-\frac{1}{2}\right)^3=-\frac{1}{8}  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Jika   an=1an  , a0a^{-n}=\frac{1}{a^n}\ \ ,\ a\ne0  maka pernyataan yang benar adalah ...

 33=273^{-3}=-27  

 33=1273^{-3}=-\frac{1}{27}  

 33=1273^{-3}=\frac{1}{27}  

 33=1273^{-3}=\frac{1}{-27}  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Hasil dari 535^3  = ...

15

45

125

243

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 (2)4\left(-2\right)^4  = ....

-16

-8

8

16

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 a2b5c3a^2b^5c^{-3}  

Bentuk pangkat positifnya adalah ....

 a2b5c3\frac{a^2b^5}{c^{-3}}  

 a2b5c3\frac{a^2b^5}{c^3}  

 a2b5c3\frac{a^2}{b^5c^3}  

 c3a2b5\frac{c^3}{a^2b^5}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 2x2y1z52x^2y^{-1}z^{-5}  bentuk pangkat positifnya adalah ....

 2x2yz5\frac{2x^2y}{z^5}  

 x22 y z5\frac{x^2}{2\ y\ z^5}  

 x2z52 y\frac{x^2z^5}{2\ y}  

 2x2y z5\frac{2x^2}{y\ z^5}  

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