Solving Compound & Absolute Value Inequalities

x + 1 ≤ -3 or -4x < -8

• x ≤ -4 or x > 2

• x ≤ -4 and x > 2

• x ≤ -2 or x > 2

• x ≤ -2 and x > 2

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

Write the inequality statement.

• x > -14 and x < 4

• x > -14 or x < 4

• x ≥ -14 and x ≤ 4

• x ≥ -14 or x ≤ 4

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.3

CCSS.HSA.REI.B.3

Write the inequality statement.

• x ≤ -3 or x > 2

• x ≤ -3 and x > 2

• x < -3 or x ≥ 2

• x < -3 and x ≥ 2

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

What inequality is shown in the picture?

• x > 6 or x < 0

• x > 6 and x < 0

• x > 6 or x < 0

• x > 6 and x < 0

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

CCSS.HSA.REI.D.12

What inequality is shown in the picture?

• x < 0 or x > 7

• x < 0 and x > 7

• x < 0 or x < 7

• x < 0 and x < 7

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.3

CCSS.HSA.REI.B.3

What inequality is graphed?

• x > 2 and x < 4
• x ≥ 2 and x ≤ 4
• x > 2 or x < 4
• x ≥ 2 or x ≤ 4

| 2x + 12 | < 8
Which is the correct first step?

• 2x + 12 < 8 and 2x+12 >-8
• 2x + 12 < 8 or 2x+12 >-8
• 2x + 12 < 8 and 2x+12 <-8
• 2x + 12 < 8 or 2x+12 >-8

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

What is the first step?

• Get the absolute value alone by dividing both sides by 5
• Drop the absolute value bars and add 7 and 5 together
• Get the absolute value alone by subtracting 5 from both sides

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

| x - 6 | < 4
Is this an "and"  or an "or" problem?

• and
• or

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

Solve: -1 < 9 + n < 17

• n > -10 or n < 8

• 8 < n < 26

• -10 < n < 8

• n > 8 or n > 26

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.3

CCSS.HSA.REI.B.3