Chọn câu đúng. Với x = a m \frac{a}{m} m a , y = b m \frac{b}{m} m b (a, b, m ∈ Z; m > 0) ta có:

x + y = a m + b m = a + b m x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a+b}{m} x + y = m a + m b = m a + b

x + y = a m + b m = a − b m x+y\ =\ \frac{a}{m}+\frac{b}{m}=\frac{a-b}{m} x + y = m a + m b = m a − b

x + y = a m + b m = a − ( + b ) m x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a-\left(+b\right)}{m} x + y = m a + m b = m a − ( + b )

x + y = a m + b m = a + ( − b ) m x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a+\left(-b\right)}{m} x + y = m a + m b = m a + ( − b )

Tính − 1 7 − 1 8 \frac{-1}{7}-\frac{1}{8} 7 − 1 − 8 1

− 15 56 \frac{-15}{56} 5 6 − 1 5

− 1 56 \frac{-1}{56} 5 6 − 1

Gía trị của x thỏa mãn 15 20 − x = 7 16 \frac{15}{20}-x=\frac{7}{16} 2 0 1 5 − x = 1 6 7 là

− 5 16 \frac{-5}{16} 1 6 − 5

− 19 16 \frac{-19}{16} 1 6 − 1 9

Tính 4 7 + − 5 4 − 3 28 \frac{4}{7}+\frac{-5}{4}-\frac{3}{28} 7 4 + 4 − 5 − 2 8 3 ta được:

− 11 14 \frac{-11}{14} 1 4 − 1 1

− 35 28 \frac{-35}{28} 2 8 − 3 5

Chọn câu đúng. Với x = a m , \frac{a}{m}, m a , y = b m \frac{b}{m} m b (a, b, m ∈ Z; m > 0) ta có:

x − y = a m − b m = a − b m x-y=\frac{a}{m}-\frac{b}{m}=\frac{a-b}{m} x − y = m a − m b = m a − b

x − y = a m − b m = a + b m x-y=\frac{a}{m}-\frac{b}{m}=\frac{a+b}{m} x − y = m a − m b = m a + b

x − y = a m − b m = a − ( − b ) m x-y=\frac{a}{m}-\frac{b}{m}=\frac{a-\left(-b\right)}{m} x − y = m a − m b = m a − ( − b )

Tổng 7 15 + − 3 5 \frac{7}{15}+\frac{-3}{5} 1 5 7 + 5 − 3 bằng

− 2 15 \frac{-2}{15} 1 5 − 2

Số đối của số − 11 − 24 \frac{-11}{-24} − 2 4 − 1 1 là:

− 11 24 \frac{-11}{24} 2 4 − 1 1

− 11 − 24 \frac{-11}{-24} − 2 4 − 1 1

− 24 11 \frac{-24}{11} 1 1 − 2 4

Chọn nhận định đúng:

N ⊂ Z ⊂ Q N\subset Z\subset Q N ⊂ Z ⊂ Q

Z ⊂ N ⊂ Q Z\subset N\subset Q Z ⊂ N ⊂ Q

N ⊂ Q ⊂ Z N\subset Q\subset Z N ⊂ Q ⊂ Z

Để cộng hai phân số có cùng mẫu số dương, ta thực hiện:

Giữ nguyên mẫu số, cộng hai tử số.

Giữ nguyên tử số, cộng hai mẫu số.

Tử số cộng tử số, mẫu số cộng mẫu số.

Với a , b , m ∈ Z a,b,m\in Z a , b , m ∈ Z và m ≠ 0 m\ne0 m  = 0 , a m − b m = \frac{a}{m\ }-\frac{b}{m}= m a − m b =

a − b m \frac{a-b}{m} m a − b

a − b m − m \frac{a-b}{m-m} m − m a − b

a − b 2 m \frac{a-b}{2m} 2 m a − b

Cộng, trừ số hữu tỉ

Authored by Nhung Trương

Mathematics

6th Grade

CCSS covered

Used 229+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Chọn câu đúng. Với x = $\frac{a}{m}$ , y = $\frac{b}{m}$
(a, b, m ∈ Z; m > 0) ta có:

$x+y\ =\ \frac{a}{m}+\frac{b}{m}=\frac{a-b}{m}$

$x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a-\left(+b\right)}{m}$

$x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a+b}{m}$

$x+y\ =\frac{a}{m}+\frac{b}{m}=\frac{a+\left(-b\right)}{m}$

Tags

CCSS.6.EE.B.6

CCSS.6.EE.A.2

CCSS.6.EE.A.3

CCSS.6.EE.A.4

CCSS.6.NS.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính $\frac{3}{4}-\frac{7}{20}$

$\frac{1}{10}$

$\frac{30}{40}$

$\frac{2}{5}$

$\frac{4}{5}$

Tags

CCSS.4.NF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính $\frac{-1}{7}-\frac{1}{8}$

$\frac{-1}{56}$

$\frac{-15}{56}$

$\frac{21}{56}$

$\frac{15}{56}$

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tìm x, biết: $x+\frac{1}{7}=\frac{11}{14}$

$\frac{9}{14}$

$\frac{1}{14}$

$\frac{11}{14}$

$\frac{1}{2}$

Tags

CCSS.6.EE.B.6

CCSS.6.EE.B.5

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Gía trị của x thỏa mãn $\frac{15}{20}-x=\frac{7}{16}$ là

$\frac{-5}{16}$

$\frac{5}{16}$

$\frac{19}{16}$

$\frac{-19}{16}$

Tags

CCSS.6.EE.B.6

CCSS.6.EE.B.5

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính $\frac{4}{7}+\frac{-5}{4}-\frac{3}{28}$ ta được:

$\frac{-35}{28}$

$\frac{11}{14}$

$\frac{22}{28}$

$\frac{-11}{14}$

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Chọn câu đúng. Với x = $\frac{a}{m},$ y = $\frac{b}{m}$
(a, b, m ∈ Z; m > 0) ta có:

$x-y=\frac{a}{m}-\frac{b}{m}=\frac{a+b}{m}$

$x-y=\frac{a}{m}-\frac{b}{m}=\frac{a-b}{m}$

$x-y=\frac{a}{m}-\frac{b}{m}=\frac{a-\left(-b\right)}{m}$

Tags

CCSS.6.EE.B.6

CCSS.6.EE.A.2

CCSS.6.EE.A.3

CCSS.6.EE.A.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tổng $\frac{7}{15}+\frac{-3}{5}$ bằng

$\frac{16}{15}$

$\frac{4}{10}$

$\frac{-2}{15}$

$\frac{2}{9}$

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Số đối của $\frac{-3}{7}$ là

$\frac{-3}{7}$

$\frac{-7}{3}$

$0$

$\frac{3}{7}$

Tags

CCSS.6.NS.C.5

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Số đối của số $\frac{-11}{-24}$ là:

$\frac{11}{24}$

$\frac{-11}{24}$

$\frac{-11}{-24}$

$\frac{-24}{11}$

Tags

CCSS.6.NS.C.5

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Cộng, trừ số hữu tỉ

Chọn câu đúng. Với x = am\frac{a}{m}ma​ , y = bm\frac{b}{m}mb​ (a, b, m ∈ Z; m > 0) ta có:

Tính 34−720\frac{3}{4}-\frac{7}{20}43​−207​

Tính −17−18\frac{-1}{7}-\frac{1}{8}7−1​−81​

Tìm x, biết: x+17=1114x+\frac{1}{7}=\frac{11}{14}x+71​=1411​

Gía trị của x thỏa mãn 1520−x=716\frac{15}{20}-x=\frac{7}{16}2015​−x=167​ là

Tính 47+−54−328\frac{4}{7}+\frac{-5}{4}-\frac{3}{28}74​+4−5​−283​ ta được:

Chọn câu đúng. Với x = am,\frac{a}{m},ma​, y = bm\frac{b}{m}mb​ (a, b, m ∈ Z; m > 0) ta có:

Tổng 715+−35\frac{7}{15}+\frac{-3}{5}157​+5−3​ bằng

Số đối của −37\frac{-3}{7}7−3​ là

Số đối của số −11−24\frac{-11}{-24}−24−11​ là:

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Discover more resources for Mathematics

Chọn câu đúng. Với x = $\frac{a}{m}$ , y = $\frac{b}{m}$
(a, b, m ∈ Z; m > 0) ta có:

Tính $\frac{3}{4}-\frac{7}{20}$

Tính $\frac{-1}{7}-\frac{1}{8}$

Tìm x, biết: $x+\frac{1}{7}=\frac{11}{14}$

Gía trị của x thỏa mãn $\frac{15}{20}-x=\frac{7}{16}$ là

Tính $\frac{4}{7}+\frac{-5}{4}-\frac{3}{28}$ ta được:

Chọn câu đúng. Với x = $\frac{a}{m},$ y = $\frac{b}{m}$
(a, b, m ∈ Z; m > 0) ta có:

Tổng $\frac{7}{15}+\frac{-3}{5}$ bằng

Số đối của $\frac{-3}{7}$ là

Số đối của số $\frac{-11}{-24}$ là: