Distance and Radicals

Distance and Radicals

9th - 12th Grade

10 Qs

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Distance and Radicals

Distance and Radicals

Assessment

Quiz

Created by

Laura Foster

Mathematics

9th - 12th Grade

7 plays

Medium

CCSS
HSG.GPE.B.7, HSN.RN.A.2, HSN.RN.A.1

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Simplify the given radical : √24

4√6

2√6

4.9

2√12

Tags

CCSS.HSN.RN.A.1

CCSS.HSN.RN.A.2

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Simplify the following radical: √32

5.7

4√8

16√2

4√2

Tags

CCSS.HSN.RN.A.2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Simplify the given radical : √72

8.5

3√8

6√2

3√4

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calculate the distance between the points: (-3, -4) and (5, 5). Give your answer in simplest radical form.

11.8

145\sqrt{145}

12

5 29\sqrt{29}

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the exact distance between each pair of points.


(-3, 5), (5, -5)

A

B

C

D

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the exact distance between each pair of points.


(-1, 4), (5, -1)

A

B

C

D

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the distance between (2,8) and (1,3).

130\sqrt{130}

26\sqrt{26}

6

52\sqrt{52}

Tags

CCSS.HSG.GPE.B.7

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the exact length between the points (-4, 3) and (-8, 1).

20

252\sqrt{5}

525\sqrt{2}

2102\sqrt{10}

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the distance formula correctly written:

d = (y1 y2)2 (x2 x1)2 d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\

d = (x2 x1)2 + (y2 y1 )2d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)2}

d = (y1 y 2)2 + (x2 x1)2d\ =\ \sqrt{\left(y_{1\ }-\ y\ _2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)}^2

d = (x)2 (y)2\sqrt{\left(x\right)^2-\ \left(y\right)^2}

Tags

CCSS.HSG.GPE.B.7

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A(2,0) B(-2,4) is written as

d = (42)2 (02)2d\ =\ \sqrt{\left(4-2\right)^2\ -\ \left(0-2\right)^2}

d = (40)2 (22)2d\ =\ \sqrt{\left(4-0\right)^2\ -\ \left(-2-2\right)^2}

d = (2 +0)2 + (4+2)2d\ =\ \sqrt{\left(-2\ +0\right)^2\ +\ \left(4+2\right)^2}

d = (22)2 + (40)2d\ =\ \sqrt{\left(-2-2\right)^2\ +\ \left(4-0\right)^2}

Tags

CCSS.HSG.GPE.B.7

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