Solving Polynomial

Solve by Factoring:
x² + 15x + 64 = 20

• {-8, 2}
• {-7, 5}
• {-11, -4}
• {-11}

Tags

CCSS.HSA.REI.B.4

Solve by Factoring:  4x² + 11x - 3 = 0

• x = -3/4 and x = -1
• x = 4 and x = 3
• x = 1/4 and x = -3
• x = -1/4 and x = 3

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Factor this difference of cubes:
x³ - 343

• (x + 7) (x² - 7x + 49)
• (x² + 1) (x - 343)
• (x - 7) (x² + 7x + 49)
• (x² - 343) (x + 1)

Tags

CCSS.HSA.APR.C.4

Factor:   x³ + 1

• (x + 1)³
• (x+1)(x² - x + 1)
• (x - 1) (x² + x - 1)
• (x + 1)(x² - 2x + 1)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.B.2

CCSS.HSA.SSE.A.2

Factor by grouping:
4p³+8p²+3p+6

• (2p²+3)(p+2)
• (2p²+6)(p+4)
• (4p²+3)(p+2)
• (4p²+8p)(3p+6)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor by grouping:
30x³+15x²-18x-9

• (5x²-3)(6x+1)
• (5x²-3)(6x+3)
• 3(5x²+3)(2x-1)
• 3(5x²-3)(2x+1)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

What are the zeros of the function?

• 4,1
• 3,1,-2,-5
• -3, -1, 2, 5
• -2,4

Tags

CCSS.HSA.APR.B.3

What is another way to say "where a function crosses the x-axis"?

• x-intercept
• zero
• root
• all of these.

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.D.11

To determine how many x-intercepts the polynomial has, look at the …

• Degree of the function

• End behavior

• Coeffients

• Y-intercept

Tags

CCSS.HSA.APR.B.3

Solve for the values of x:
(x - 5)(x - 1) = 0

• { 5, 1 }
• { 5, -1 }
• { -5, 1 }
• { -5, -1 }

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4