Solving Log and Exponential Equations

log₂(2) + log₂(8x) = 6

• x = 3
• x = 2
• x = 6
• x = 4

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

log₆(2x + 3) = 3

• x = 106.5
• x = 100
• x = 16
• x = 50

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

log x - log 8 = 3

• x = 1000

• x = 800

• x = 8000

• x = 100

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.BF.B.5

log₅ (2x - 3)² = 6

• x = 128
•  x = 64
• x = 4
• x = 14

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Write as a single log: log 12 + 2 log x

• log (12 + 2x)
• log (14x)
• log (12 * 2x)
• log (12x²)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

Use the change of base rule to rewrite this problem:

log₃64

• log(64)/log(3)

• log(3)/log(64)

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

3^{2x – 6}  = 81

• x = log 4
• x = 5
• x = 4
• x = -1

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

• $\left\{\frac{11}{5}\right\}$

• $\left\{-1\right\}$

• $\left\{-5\right\}$

• No Solution.

Tags

CCSS.HSA.REI.A.2

• $\left\{-\frac{1}{3}\right\}$

• $\left\{4\right\}$

• No solution.

• $\left\{6\right\}$

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.A.2