Solving equation quiz

Which operation will cancel out multiplication?

• A.  Addition
• B. Subtraction
• C. Multiplication
• D. Division

Tags

CCSS.3.OA.C.7

What is the first step in solving this equation:
5x + 7 = 12

• Divide by 5
• Subtract 5
• Multiply by 7
• Subtract 7

Tags

CCSS.7.EE.B.4A

What step would you take to solve this equation?

• Multiply both sides of the equation by 2
• Divide both sides of the equation by 2
• Add 2 to both sides of the equation
• Subtract 2 from both sides of the equation

Tags

CCSS.6.EE.B.7

Find the error in the problem below

 $19-2k=3k-1$  
    $+3k$    $+3k$  
 $19+1k=-1$  
 $-19\ \ \ \ \ \ \ \ \ \ -19$ 
  $k=-20$  

• They should have divided by 1 for the last step

• They should add 19 instead of subtracting 19

• I can not find an error

• Instead of adding 3k they should subtract 3k

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

The first step to solving the equation g - 3 = -12 is to . . .

• divide by -3 on both sides of the equal sign

• multiply by -3 on both sides of the equal sign

• subtract 3 on both sides of the equal sign

• add 3 on both sides of the equal sign

Tags

CCSS.6.EE.B.7

g - 3 = -12, after you add 3 on both sides of the equal sign, what is your answer?

• g = -15

• g = -9

• g = 36

• g = 15

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Solve. Look very closely, click on picture to enlarge

• 12

• 13

• 14

• 15

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Distribute 5(b - 2) and you get . . .

• 5b - 2

• 5b - 10

• 5b + 10

• 3b

Tags

CCSS.6.EE.A.3

Solve the equation 5(b - 2) = -10

• b = 4

• No answer

• b = 2

• b = 0

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

In the equation  $5d-1=2d-7,$  What would you do to move the VARIABLE to the LEFT side?

• -2 from both sides of the equal sign

• -5d from both sides of the equal sign

• -2d from both sides of the equal sign

• + 7 on both sides of the equal sign

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7