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Mid point and Distance

Authored by Allyssa Amaya

Mathematics

10th Grade

CCSS covered

Used 137+ times

Mid point and Distance
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9 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What's the distance between (-11,4) and (4,4)?

-15
15
7
-7

Tags

CCSS.HSG.GPE.B.7

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What's the distance between (0,0) and (3,4)

7
49
5
25

Tags

CCSS.6.NS.C.8

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

If point A is at (-2, 9) and point B is located at (6,-3), then find the coordinate for the mid-point of segment AB.

(4, 6)

(4, -6)

(2, 3)

(2, 0)

Tags

CCSS.HSG.GPE.B.6

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

M (1, −2) is the midpoint of segment GH , and G has coordinates (3, 4). Find the coordinates of H.

H (10)

H (2, 1)

H (-2, -1)

H (-1, -8)

Tags

CCSS.HSG.GPE.B.6

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Point M is the midpoint of segment JK. The coordinate for point M is (1,1) and point K is (8,3). Find the coordinate for point J.

J (6, -1)

J (-6, -1)

J (-6, 1)

J (6, 1)

Tags

CCSS.HSG.GPE.B.6

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

How is the distance formula correctly written:

d = (y1 y2)2 (x2 x1)2 d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\

d = (x2 x1)2 + (y2 y1 )2d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)2}

d = (y1 y 2)2 + (x2 x1)2d\ =\ \sqrt{\left(y_{1\ }-\ y\ _2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)}^2

d = (x)2 (y)2\sqrt{\left(x\right)^2-\ \left(y\right)^2}

Tags

CCSS.HSG.GPE.B.7

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the distance between the points (4, 3) and (0, 6).

3
4
5
7

Tags

CCSS.HSG.GPE.B.7

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