Kinematic Equation Identification 2

Choose which Formula you should choose to solve for the following word problem provided?

" A 3000 kg truck traveling at a speed of 60 m/s slows at a uniform rate until it comes to a stop in 5.2 seconds. How much distance is covered while stopping?"

• Δx = (.5)(Vi+Vf)t

• Vf = Vi + (at)

• Δx =(Vi*t) + (.5)(a)(t2)

• Δx =(Vf*t) - (.5)(a)(t2)

• Vf2= Vi2 + (2aΔx)

Answer explanation

Vf=0 m/s

Vi=60 m/s

a=N/A

t=5.2 sec

x=?

Which Formula should you choose to solve for the following word problem provided?

" An airplane starts from rest and hits a liftoff speed of 52.78 m/s in a time of 3.48 seconds. What is the minimum length of a runway for this plane?"

• Δx = (.5)(Vi+Vf)t

• Vf = Vi + (at)

• Δx =(Vi*t) + (.5)(a)(t^2)

• Δx =(Vf*t) - (.5)(a)(t2)

Answer explanation

Vf=52.78 m/s

Vi=0 m/s

a=N/A

t=3.48 sec

x=?

Tags

NGSS.HS-PS2-1

Which Formula should you choose to solve for the following word problem provided?

" A 70 kg cart slows from 8.2 m/s to 1.58 m/s in a distance of 11.55 m. What is the deceleration rate of the cart?"

Answer explanation

Vf=1.58 m/s

Vi=8.2 m/s

a=?

t=N/A

x=11.55m

Tags

NGSS.HS-PS2-1

Which Formula would you choose first to begin the process of solving this problem?

" A car traveling at 70 m/s accelerates to 97 m/s in 5.5 seconds. How far did it travel in that period of time?"

Answer explanation

Vf=1.58 m/s

Vi=8.2 m/s

a=N/A

t=5.5 sec

x=?

" A woman walks 780 meters in 25 minutes. Convert the minutes to seconds.

Convert the 25 minutes into seconds.

• 1500 sec

• 1500 min

• 0.417 sec

• 2.4 sec

Answer explanation

25 min/1 x 60sec/1min = 25 (60)sec = 1500 sec

Now that you have solved for acceleration, which formula should you choose to solve for displacement (x)?

" A woman walks 780 meters in 25 minutes. Convert the minutes to seconds and determine her average velocity in m/s?"

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Answer explanation

Vf =?

Vi =0 m/s

a = N/A

t=____sec

x=780 m

Which formula should you choose to solve for the following word problem below?

"What is the acceleration when an object traveling at 5.2 m/s accelerates to 33.8 m/s over a distance of 500m?"

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Answer explanation

Vf =33.8 m/s

Vi =5.2 m/s

a = ?

t=N/A

x=500 m

Which formula should you choose to solve for the following word problem below?

"What is the distance covered when an object at rest on a ledge falls for 9.2 seconds?"

Answer explanation

Vf =N/A

Vi =0 m/s (from at rest)

a = -9.8 m/s²

t= 9.2 sec

Y=?