review  REI.1, CED.4, CED.1, RN.3

review REI.1, CED.4, CED.1, RN.3

9th - 12th Grade

14 Qs

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review  REI.1, CED.4, CED.1, RN.3

review REI.1, CED.4, CED.1, RN.3

Assessment

Quiz

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
HSA.REI.A.1, HSA.CED.A.4, 8.EE.C.8C

+4

Standards-aligned

Created by

Kim Lott

Used 22+ times

FREE Resource

14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which property was used between step 1 and Step 2

Given: 4(x - 3) = 8

Step 1: x - 3 = 2

Step 2: x = 5

subtraction of equality

distributive property

addition of equality

division of equality

Tags

CCSS.HSA.REI.A.1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which property was used between Given and Step 1

Given: 4(x - 3) = 8

Step 1: x - 3 = 2

Step 2: x = 5

distributive property

multiplication of equality

division of equality

commutative property

Tags

CCSS.HSA.REI.A.1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where was the 1st mistake made?
Given: 7 = 2(3x - 4)
Step 1: 2(3x - 4) = 7
Step 2: 6x - 6 = 7
Step 3: 6x = 13
Step 4: x =  613\frac{6}{13}  

Step 1

step 2

step 3

step 4

Tags

CCSS.HSA.REI.A.1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which step contains the 1st error? -2(x - 4) - 2 < 2

Step 1: -2x + 8 - 2 < 2

Step 2: -2x + 6 < 2

Step 3: -2x <-4

Step 4: x < 2

Step 1

step 2

step 3

step 4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 A=πr2     Solve for fA=\pi r^2\ \ \ \ \ Solve\ for\ f  

 r = Aπr\ =\ \frac{A}{\pi}  

 r = Aπr\ =\ \sqrt{\frac{A}{\pi}}  

r =  πA\frac{\pi}{A}  

r =  πA\sqrt{\frac{\pi}{A}}  

Tags

CCSS.HSA.CED.A.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

-2x + 3y = 15

y = 23x + 5y\ =\ \frac{-2}{3}x\ +\ 5

y = 23x + 5y\ =\ \frac{2}{3}x\ +\ 5

y = 23x +15y\ =\ \frac{2}{3}x\ +15

y = 23x + 15y\ =\ \frac{-2}{3}x\ +\ 15

Tags

CCSS.6.EE.C.9

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 A=13πr2h     solve for hA=\frac{1}{3}\pi r^2h\ \ \ \ \ solve\ for\ h  

 h = A3πr2h\ =\ \frac{A}{3\pi r^2}  

 h = A3πrh\ =\ \frac{A}{3\pi r}  

 h = 3Aπr2h\ =\ \frac{3A}{\pi r^2}  

 h = 3Aπrh\ =\ \frac{3A}{\pi r}  

Tags

CCSS.HSA.CED.A.4

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