DBM 20023 : Basic Rules of Differentiation

 $10x^4-6x^2+2x$  

 $10x^4+6x^2-2x$  

 $10x^4+6x^2+2x$  

 $10x^4-6x^2-2x$  

 $\frac{dy}{dx}=8x^7-12x^5-3x^2-4x$  

 $\frac{dy}{dx}=8x^7+12x^5-3x^2-4$  

 $\frac{dy}{dx}=8x^7+12x^5+3x^2+4x$  

 $\frac{dy}{dx}=8x^7-12x^5+3x^2+4$  

 $\frac{5}{2}x^{\frac{7}{2}}$  

 $\frac{5}{2}x^{\frac{1}{2}}$  

 $\frac{1}{2}x^{\frac{3}{2}}$  

 $\frac{5}{2}x^{\frac{3}{2}}$  

 $\frac{dy}{dx}=\frac{1}{2\sqrt{x}}+\frac{2}{3x}+10x$  

 $\frac{dy}{dx}=\frac{1}{\sqrt{x}}-\frac{2}{3x}+10$  

 $\frac{dy}{dx}=\frac{1}{2\sqrt{x}}+\frac{2}{3x^3}+10$  

 $\frac{dy}{dx}=\frac{1}{2\sqrt{x}}-\frac{2}{3x^3}+10$  

 $f'\left(x\right)=3x^2-3+4x$  

 $f'\left(x\right)=3x^2-3x+4x-6$  

 $f'\left(x\right)=3x^2-3+4x-6$  

 $f'\left(x\right)=x^3-3x+2x^2-6$  

 $\frac{dy}{dx}=4x^2-\frac{2}{x^2}+\frac{12}{x^3}$  

 $\frac{dy}{dx}=4x-\frac{2}{x^3}+\frac{12}{x^4}$  

 $\frac{dy}{dx}=4x^2+\frac{2}{x^3}-\frac{12}{x^4}$  

 $\frac{dy}{dx}=4x+\frac{1}{2x^3}-\frac{12}{x^4}$  

 $f'\left(x\right)=5x^4+6x^2-10x$  

 $f'\left(x\right)=5x^4-6x^2-10x$  

 $f'\left(x\right)=5x^4+6x^2+10x$  

 $f'\left(x\right)=5x^4-6x^2+10x$  

 $\frac{dy}{dx}=-10x\left(1-x^2\right)^6$  

 $\frac{dy}{dx}=10x\left(1-x^2\right)^4$  

 $\frac{dy}{dx}=-10x\left(1-x^2\right)^4$  

 $\frac{dy}{dx}=10\left(1-x^2\right)^4$  

 $f'\left(x\right)=\frac{-4}{\left(2x+5\right)}$  

 $f'\left(x\right)=\frac{-4}{\left(2x+5\right)^3}$  

 $f'\left(x\right)=\frac{4}{\left(2x+5\right)^2}$  

 $f'\left(x\right)=\frac{-4}{\left(2x+5\right)^2}$  

 $f'\left(x\right)=\frac{-2x}{\sqrt{1-2x^2}}$  

 $f'\left(x\right)=\frac{2x}{\sqrt{1-2x^2}}$  

 $f'\left(x\right)=-2x\sqrt{1-2x^2}$  

 $f'\left(x\right)=\frac{-4x^2}{\sqrt{1-2x^2}}$