Search Header Logo

Trig differentiation

Authored by Alison THOMPSON

Mathematics

12th Grade

Used 10+ times

Trig differentiation
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

To differentiate

 y=sec3xy=\sec^3x  I should use

Product rule

Quotient rule

Chain rule

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt


 sin(x2+1)\sin\left(x^2+1\right)  differentiates to

 2xsin(x2+1)+cos(x2+1)2x\sin\left(x^2+1\right)+\cos\left(x^2+1\right)  

 2xsin(x2+1)2x\sin\left(x^2+1\right)  

 2xcos(x2+1)2x\cos\left(x^2+1\right)  

 cos(x2+1)+sin(2x)\cos\left(x^2+1\right)+\sin\left(2x\right)  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

To show that

 tan x\tan\ x  differentiates to  sec2x\sec^2x   I must use the

Chain rule

Product rule

Quotient rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 y=tan(3x)y=\tan\left(3x\right)  then  dydx=\frac{dy}{dx}=  


 3sec(3x)3\sec\left(3x\right)  

 sec2(3x)\sec^2\left(3x\right)  

 3xsec2(3x)3x\sec^2\left(3x\right)  

 3sec2(3x)3\sec^2\left(3x\right)  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 y=cosec(10x+4)y=\operatorname{cosec}\left(10x+4\right)  find  dydx\frac{dy}{dx}  

 10cosec(10x+4)cot(10x+4)-10\operatorname{cosec}\left(10x+4\right)\cot\left(10x+4\right)  

 10cosec(10x+4)cot(10x+4)10\operatorname{cosec}\left(10x+4\right)\cot\left(10x+4\right)  

 10cosec(10x+4)-10\operatorname{cosec}\left(10x+4\right)  

 10cosec(10x+4)cot(10x+4)10\operatorname{cosec}\left(10x+4\right)\cot\left(10x+4\right)  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 y=tanxxy=\frac{\tan x}{x}  find  dydx\frac{dy}{dx}  



 xsec2xtanxx\sec^2x-\tan x  

 xsec2x+tanxx\sec^2x+\tan x  

 xsec2xtanxx2\frac{x\sec^2x-\tan x}{x^2}  

 sec2x1\frac{\sec^2x}{1}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Differentiate excotxe^x\cot x  


 excosec2x-e^x\operatorname{cosec}^2x  

 ex(cotxcosec2x)e^x\left(\cot x-\operatorname{cosec}^2x\right)  

 xexcotxexcosec2xxe^x\cot x-e^x\operatorname{cosec}^2x  

 excotxcosec2xe^x\cot x-\operatorname{cosec}^2x  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?