Solving Polynomials

x² + 12x + 32 = 0

• x = -4, 8

• x = 4, 8

• x = -4, -8

• x = 0, 12

Tags

CCSS.HSA-REI.B.4B

Solve the equation by factoring:

n²+11n +30 = 0

• n - -6, -5

• n = 6, 5

• n = 2, 15

• n = -2, -15

Tags

CCSS.HSA-REI.B.4B

What should be the order of the polynomial coefficients if
(3x - 4x³ + 6x⁴ + 1) / (x + 3)

• 3   0   -4   6   1
• 6   -4   3   1   0
• 6   -4   0   3   1
• -6   4   0   -3   -1

Tags

CCSS.HSA.APR.D.6

(2x³ - 5x² + 3x + 7) ÷ (x - 2)

• 2x³ - x² + x + 9
• 2x² - x + 1
• 2x² - x + 1 + 9/x-2
• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.D.6

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

(3x³ - 2x² - 7x + 6) ÷ (x + 1)

• 3x³ - 5x² - 2x + 8
• 3x² + x - 6
• 3x² - 5x - 2 + 8/x+1
• 3x³ + x² - 6x

Tags

CCSS.HSA.APR.D.6

Solve by using Rational Root Theorem: 
x³ - 7x - 6 = 0

• 1, 2, 3
• -1, -2, - 3
• -1, -2, 3
• 1,-2,-3

Tags

CCSS.HSA.APR.B.2

Solve by using Rational Root Theorem: 
x³ + 3x² - 6x - 8 = 0

•  -4, -1, 2
• -4, -1, ±√2
• 1, 2, 4
• 4,-1,√2

Tags

CCSS.HSF-IF.C.7C

Below are four possible zeros for this polynomial.

Figure out which one "works"

f(x) = x³ + 2x² - 11x - 12

• -3

• -4

• 1

• 6

Tags

CCSS.HSF-IF.C.7C

Below are four possible zeros for this polynomial.

Figure out which one "works"

f(x) = x³ - 8x² - 23x + 30

• 3

• -1

• -10

• 1

Tags

CCSS.HSF-IF.C.7C