3 5 ⋅ 8 = \frac{3}{5\cdot\sqrt{8}}= 5 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 3 =

3 ⋅ 8 40 \frac{3\cdot\sqrt{8}}{40} 4 0 3 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 ⋅ 8 5 \frac{3\cdot\sqrt{8}}{5} 5 3 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 ⋅ 8 5 ⋅ 8 \frac{3\cdot\sqrt{8}}{5\cdot\sqrt{8}} 5 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 3 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 ⋅ 8 5 \frac{3\cdot\sqrt{8}}{5} 5 3 ⋅ 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

48 − 27 − 12 + 3 = \sqrt{48}-\sqrt{27}-\sqrt{12}+\sqrt{3}= 4 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> =

5 ⋅ 3 5\cdot\sqrt{3} 5 ⋅ 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 ⋅ 3 2\cdot\sqrt{3} 2 ⋅ 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Négyzetgyök Quiz

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Add meg a $\sqrt{5x+20}$ kifejezés értelmezési tartományát!

$x\ge-4$

$x>4$

$x>-4$

$x\le-4$

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\sqrt{48}\cdot\sqrt{3}=$

12

3

4

16

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\frac{\sqrt{48}}{\sqrt{3}}=$

4

3

16

8

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\left(\sqrt{7}\right)^3\cdot\sqrt{7}=$

49

7

14

21

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\frac{\left(\sqrt{7}\right)^3}{\sqrt{7}}=$

7

49

14

21

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\left(\sqrt{8}+5\right)^2=$

$33+10\cdot\sqrt{8}$

$33+5\cdot\sqrt{8}$

$25+5\cdot\sqrt{8}$

$89+10\cdot\sqrt{8}$

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\left(\sqrt{9}+\sqrt{5}\right)\cdot\left(\sqrt{9}-\sqrt{5}\right)=$

4

14

106

45

8.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

$\frac{3}{5\cdot\sqrt{8}}=$

$\frac{3\cdot\sqrt{8}}{40}$

$\frac{3\cdot\sqrt{8}}{5}$

$\frac{3\cdot\sqrt{8}}{5\cdot\sqrt{8}}$

$\frac{3\cdot\sqrt{8}}{5}$

9.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

$Melyik\ a\ nagyobb?\ A=10\cdot\sqrt{3}\ vagy\ B=2\cdot\sqrt{50}$

A

B

egyenlőek

nem tudom

10.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\sqrt{48}-\sqrt{27}-\sqrt{12}+\sqrt{3}=$

0

3

$5\cdot\sqrt{3}$

$2\cdot\sqrt{3}$

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Négyzetgyök

Add meg a 5x+20\sqrt{5x+20}5x+20​ kifejezés értelmezési tartományát!

48⋅3=\sqrt{48}\cdot\sqrt{3}=48​⋅3​=

483=\frac{\sqrt{48}}{\sqrt{3}}=3​48​​=

(7)3⋅7=\left(\sqrt{7}\right)^3\cdot\sqrt{7}=(7​)3⋅7​=

(7)37=\frac{\left(\sqrt{7}\right)^3}{\sqrt{7}}=7​(7​)3​=

(8+5)2=\left(\sqrt{8}+5\right)^2=(8​+5)2=

(9+5)⋅(9−5)=\left(\sqrt{9}+\sqrt{5}\right)\cdot\left(\sqrt{9}-\sqrt{5}\right)=(9​+5​)⋅(9​−5​)=

35⋅8=\frac{3}{5\cdot\sqrt{8}}=5⋅8​3​=

Melyik a nagyobb? A=10⋅3 vagy B=2⋅50Melyik\ a\ nagyobb?\ A=10\cdot\sqrt{3}\ vagy\ B=2\cdot\sqrt{50}Melyik a nagyobb? A=10⋅3​ vagy B=2⋅50​

48−27−12+3=\sqrt{48}-\sqrt{27}-\sqrt{12}+\sqrt{3}=48​−27​−12​+3​=

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Add meg a $\sqrt{5x+20}$ kifejezés értelmezési tartományát!

$\sqrt{48}\cdot\sqrt{3}=$

$\frac{\sqrt{48}}{\sqrt{3}}=$

$\left(\sqrt{7}\right)^3\cdot\sqrt{7}=$

$\frac{\left(\sqrt{7}\right)^3}{\sqrt{7}}=$

$\left(\sqrt{8}+5\right)^2=$

$\left(\sqrt{9}+\sqrt{5}\right)\cdot\left(\sqrt{9}-\sqrt{5}\right)=$

$\frac{3}{5\cdot\sqrt{8}}=$

$Melyik\ a\ nagyobb?\ A=10\cdot\sqrt{3}\ vagy\ B=2\cdot\sqrt{50}$

$\sqrt{48}-\sqrt{27}-\sqrt{12}+\sqrt{3}=$